Help me please, Thanks

Suppose vanilla beans cost $600 per kilogram. Julie bought 9 grams of vanilla beans. Jacques bought 70 grams of vanilla beans.

Ksju [112]

Answer:

The Correct option is 36.60

Step-by-step explanation:

The key to solving this question lies around measurement conversion,specifically converting grams into its equivalence in kilograms.

1000 grams equal one kilogram

9 grams=9/1000 kg

9 grams=0.009 kg

70 grams=70/1000 kg

70 grams=0.07 kg

Julie pays=$600*0.009=$5.4

Jacques pays=$600*0.07=$42

Jacques pays $36.60 more ($42-$5.4) than Julie paid

Option is wrong because that was what Julie paid

Option D is wrong because that was what Jacques paid

Option B is obviously wrong

3 0

3 years ago

A car travels 20 feet in 1/5 second. At this same speed, how many feet will it travel in three seconds?

MrRissso [65]

<span>if it is travelling 20 feet in 1/5 of a second that means that in 1 second (which is 5 times as much as 1/5 of a second) it will do 5 times 20 feet hence 100 feet. Then in 3 seconds it will do 300 feet</span>

8 0

4 years ago

Sarah walked at a constant speed of 20 blocks per hour. If she walked for 30 minutes how many blocks did she walk?

Afina-wow [57]

Answer:

She walked 10 blocks

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A professor of women's studies is interested in determining if stress affects the menstrual cycle. Ten women are randomly sample

BabaBlast [244]

Answer:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

$t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73$

$df=5+5-2=8$

$t_{crit}=\pm 2.306$

Reject H0: stress affects the menstrual cycle

Step-by-step explanation:

The statistic is given by the following formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2 \neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =2$ represent the sample size for group 2

Tha data given is:

Group 1 (High stress) : 20,23,18,19,22

Group 2 (Relatively stress free): 26,31,25,26,30

We can calculate the sample mean and the sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}$

$\bar X_1 =20.4$ represent the sample mean for the group 1

$\bar X_2 =27.6$ represent the sample mean for the group 2

$s_1=2.074$ represent the sample standard deviation for group 1

$s_2=2.702$ represent the sample standard deviation for group 2

And now we can calculate the statistic:

$t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73$

Now we can calculate the degrees of freedom given by:

$df=5+5-2=8$

Now we can calculate the critical value since the confidence is 95% the value for the significance would be $\alpha=1-0.95=0.05$ and the value for $\alpha/2 =0.025$ and if we find a critical value on th t distribution with 8 degrees of freedom that accumulates 0.025 of the area on each tail we got $t_{crit}=\pm 2.306$

Since our calculated value is lower than the critical value, we have enough evidence to reject the null hypothesis. And makes sense say that the difference between the two means are different at 5% of significance.

Reject H0: stress affects the menstrual cycle

5 0

3 years ago

Explain how a table can be used to find the rate of change?

tangare [24]

You find how y and x change and then divide y/x to get your rate of change

6 0

3 years ago