How many moles of UF6 would have to be decomposed to provide enough fluorine to prepare 8.99 mol of CF4? (Assume sufficient carb
on is available).
1 answer:
Answer:
5.99 moles of 
Explanation:
In this case, we can start with the <u>decomposition</u> of
, so:
<u>(Reaction 1)</u>
The
can react with carbon to produce
:
<u>(Reaction 2)</u>
If we 8.99 mol of
, we can calculate the moles of
that we need. In reaction 2 we have a <u>molar ratio</u> of 1:2 (2 moles of
will produce 1 mol of
):

With this value and using the <u>molar ratio</u> in reaction 1 (3 moles of
are producing by each mol of
), so:

So, we will need 5.99 moles of
to produce 8.99 mol of
.
I hope it helps!
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