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Katyanochek1 [597]
3 years ago
15

What kind of cells are produced at the end of meiosis?

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
7 0
Cells with haploid or N number of chromosomes are produced at the end of meiosis. in this division the number of chromosomes are halved. so daughter cells have half the number of chromosomes of the parent cell.
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The maximum amount of solute that dissolves in a given amount of solvent and forms a stable solution is called the
denis23 [38]

Answer:

The maximum amount of solute that dissolves in a given amount of solvent and forms a stable solution is called the solubility of the solute

Explanation:

The maximum amount of solute that could be dissolved in a given amount of solvent is the solubility of the solute. It is the saturated solution's concentration from where a saturated solution can be defined as the one which already contains the maximum quantity of dissolved solute at a specified temperature, while an unsaturated solution is one with a capacity to dissolve more solutes

3 0
3 years ago
PLSSSS HELP<br> this is science
jenyasd209 [6]

Answer:

<h2>The answer is C </h2>

Explanation:

when a car begins to slow down the speed that it was going will decrease. Which means that it is an example of deceleration.

4 0
3 years ago
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When non metals react with other elements and compounds what happens to their valence electrons?
DiKsa [7]

Answer:

d

Explanation:

they either gain valence electrons or share them depending on what elements or compound they are reacting with

5 0
3 years ago
0.0200 moles of a compound is found to have a mass of 1.64 g. Find the formula mass of the compound
KatRina [158]

Answer: 82.0 g/mole

Explanation:

Use the units to see that if we divide 1.64 grams by 0.0200 moles, we'll get a number that is grams/mole, the definition of formula mass.

1.64/0.0200 = 82.0 g/mole (3 sig figs)

We can't tell from this alone what the molecular formula might be, but C6H10 (cyclohexene) comes close (82.1 grams/mole).

3 0
3 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

6 0
3 years ago
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