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Yuliya22 [10]
3 years ago
7

2. Explain what type of chemical reaction is taking place, and what evidence you have to support your conclusion.

Chemistry
1 answer:
Sonja [21]3 years ago
6 0
I cant see the chemical reaction taking place, and what is the evidence to support it
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Suppose a 48. L reaction vessel is filled with 1.6 mol of Br2 and 1.6 mol of OCl2. What can you say about the composition of the
Sladkaya [172]

Answer:

There will be very little of BrOCl BrCl

Explanation:

Based on the equilibrium:

Br2(g) + OCl2(g) ⇄ BrOCl(g) + BrCl(g)

The equilibrium constant, Kc, is:

Kc = 1.58x10⁻⁵ = [BrOCl] [BrCl] / [Br2] [OCl2]

As Kc is <<< 1, in equilibrium, the concentration of products will remain lower regard to the concentration of the reactants. That means, right answer is;

<h3>There will be very little of BrOCl BrCl</h3>
7 0
3 years ago
Hi, May I have Chem help please? Please Keep the answer as simple as possible because it is a for a bcr.
finlep [7]

Proton:

Mass = 1

Charge = +1

Location = Nucleus

Neutron:

Mass = 1

Charge = 0

Location = Nucleus

Electron:

Mass = 1/2000

Charge = -1

Location = Energy levels

6 0
3 years ago
Explain how the principal of uniformitarianism is used to interpret earths past
vesna_86 [32]

Answer:

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3 0
3 years ago
Can someone tell me how to identify the number of significant figures?
igor_vitrenko [27]

Answer:

Non-zero digits are always significant.

Any zeros between two significant digits are significant.

A final zero or trailing zeros in the decimal portion ONLY are significant. If a number ends in zeros to the right of the decimal point, those zeros are significant.

Explanation:

1.138 has 4 significant figures, which are 1, 1, 3 and 8. The numbers after the decimal point are decimals and are significant figures.

8 0
3 years ago
How many times higher is the concentration of H+ in the Hubbard Brook sample than in unpolluted rainwater?
Anna [14]

Answer:

1. 7 (a neutral solution)

Answer: 10-7= 0.0000001 moles per liter

2. 5.6 (unpolluted rainwater)

Answer: 10-5.6 = 0.0000025 moles per liter

3. 3.7 (first acid rain sample in North America)

Answer: 10-3.7 = 0.00020 moles per liter

The concentration of H+ in the Hubbard Brook sample is 0.00020/0.0000025, which is 80 times higher than the H+ concentration in unpolluted rainwater.

Explanation:

8 0
2 years ago
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