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3 years ago

HI HELP ITS A QUIZZZ!

Mathematics

1 answer:

Virty [35]3 years ago

4 0

B. Its suggesting something bigger than -5

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If y = (x 3)2, and the value of x=5, what is the value?

Viktor [21]

Y=(x3)2
if x=5
y=(5.3)2
=(15)2
=30

3 0

3 years ago

Are all isosceles triangles similar? Are all right triangle similar? Are all isosceles right triangles similar? Explain.

Alex17521 [72]

9514 1404 393

Answer:

a) no

b) no

c) yes

Step-by-step explanation:

a) Isosceles triangles can have a third angle (the one that is not part of the pair of equal angles) with any value in the range 0 < α < 180°. Triangles with different angle values will not be similar.

Not all isosceles triangles are similar.

b) The smallest acute angle of a right triangle can have any measure in the range 0 < α ≤ 45°. Right triangles having different smallest angles will not be similar. The attachment shows dissimilar right triangles.

Not all right triangles are similar.

c) If the smallest acute angle of a right triangle is 45°, then both acute angles are 45°, and the right triangle is an isosceles triangle. Each such triangle will be similar to every such triangle.

All isosceles right triangles are similar.

5 0

3 years ago

The distance between a skier on top of a mountain and the end of the ski course is 2395 feet if the end of the course is 642 bel

Sunny_sXe [5.5K]

I think it is 3037 feet

6 0

3 years ago

Read 2 more answers

If 6x + 5y = 10, what is y in terms of x?<br> Please include an explanation!

Mnenie [13.5K]

what you're trying to do is form an equation for y

6x + 5y = 10

5y = -6x + 10 we need y to be singular so divide by numeral before y

y = - 6x/5 + 10/5

y = - 6x/5 + 2

6 0

2 years ago

Determine the equation of the tangent line to the given path at the specified value of t. (sin(7t), cos(7t), 2t9/2); t=1

Reptile [31]

Answer:

P(t) = {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

Step-by-step explanation:

The equation of the tangent line to the given path at the specified value of t is expressed as;

P(t) = f(t0) + f'(t0)(t - t0)

f(t0) = (sin(7t), cos(7t), 2t^9/2)

at t0 = 1;

f(t0) = {sin7(1), cos7(1), 2(1)^9/2}

f(t0) = {sin7, cos7, 2}

f'(t0) = (7cos7t, -7sin7t, 9/2{2t^9/2-1}

f'(t0) = (7cos7t, -7sin7t, 9t^7/2}

If t0 = 1

f'(1) = (7cos7(1), -7sin7(1), 9(1)^7/2)

f'(1) =(7cos7, -7sin7, 9)

Substituting the given function into the tangent equation will give:

P(t) = f(t0) + f'(t0)(t - t0)

P(t)= {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

The final expression gives the equation of the tangent line to the path.

4 0

3 years ago