No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
60%
I pretty sure this is right
Answer:
He must work additional 8 hours.
Step-by-step explanation:
Because 1550.00/20=7.75
217.00/7.75=28
28-20=8
So,an additional of 8 hours
<span>24:6 in simplest form is 4</span>
