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Rasek [7]
3 years ago
10

Solve{a 1/2 • b 1/3}^-3 ​

Mathematics
1 answer:
UNO [17]3 years ago
5 0

Step-by-step explanation:

so this what I found hope you a good luck

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In ΔHIJ, the measure of ∠J=90°, IH = 65, HJ = 56, and JI = 33. What is the value of the sine of ∠I to the nearest hundredth?
solmaris [256]

Answer:

0.86

Step-by-step explanation:

Draw the triangle.

Since ∠J=90°, this is a right triangle, so we can use SOH-CAH-TOA to find sin∠I.

sin∠I = 56/65

sin∠I = 0.86

5 0
3 years ago
Which number has a value between -8.423 and -8.395?
pav-90 [236]

Answer:

Step-by-step explanation:

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2 years ago
Anna has a collection of 45 nickels and quarters worth $8.05. How many nickels does she have?
madreJ [45]
It could be 1, I'm not really sure
3 0
3 years ago
Which autocad command can we use to quickly calculate the area and perimeter of a closed region defined by a polyline?
polet [3.4K]

The answer is: The Area command.

The explanation is shown below:

1. The Area command is a very useful command in AutoCad, and you can use it to calculate  the area and the perimeter of a closed region draw with a polyline.

2. To use this command, you only need to type AREA and press the enter button. Then, you must select the points of the closed region and press enter again. Once you do this, the software will show you the perimeter and the area.

4 0
3 years ago
Please help answer the question.
muminat

Answer:

a. \dfrac{y^8}{x^{10}}

Step-by-step explanation:

First step is ti distribute the exponent outside the parenthesis. According to the law of exponents, you need to distribute it to each variable.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}\\\\=\dfrac{x^{(-4\times-2)}y^{(1\times-2)}}{x^{(-9\times-2)}y^{(5\times-2)}}\\\\=\dfrac{x^{8}y^{-2}}{x^{18}y^{-10}}

Now again, following the law of exponents, if you have negative exponents, you put them in the opposite side of the fraction.

=\dfrac{x^8y^{-2}}{x^{18}y^{-10}}\\\\=\dfrac{x^8y^{10}}{x^{18}y^{2}}\\\\

Next, when it comes to division, we subtract the exponents of the numerator and the denominator of similar variables.

=\dfrac{x^8y^{10}}{x^{18}y^{2}}\\\\=x^{(8-18)}y^{(10-2)}\\\\=x^{-10}y^8

Since the exponent of x is negative, we move it below the fraction.

\dfrac{y^8}{x^{10}}

6 0
3 years ago
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