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3 years ago

10

PLEASE HELP!!

2 answers:

Evgesh-ka [11]3 years ago

7 0

C or D. But it doesn't say that Chelley went to go get the water from her car to bring it in the park.

D. would = $4

C. would = $5

But since it doesn't say that Chelley went to get them it would be C

11Alexandr11 [23.1K]3 years ago

4 0

C. Bailey because she REFILLS the water inside the park at the fountain for free. She only spent $5

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What is the value of n 9 times 27+2 times31-28

Kay [80]

9•27+2•31-28= ? Is that what you are asking?

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3 years ago

What is 1/12x(4+6x3)-9?

sertanlavr [38]

Your answer is -43/6

1/12(4+6x3)-9
=1/12(22)-9
=11/6-9
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6 0

3 years ago

Select the correct answer.

Ierofanga [76]

Answer:

$19.2x+96$ units

Step-by-step explanation:

The perimeter of a square is 4 times the length of one side.

The length of the sides of a square is given by the expression $4.8x+24$

To find the perimeter, we multiply this expression by 4.

$Perimeter=4(4.8x+24)$

We expand to obtain:

$Perimeter=4*4.8x+4*24$

This simplifies to:

$Perimeter=19.2x+96$

7 0

3 years ago

The petronas towers in Kuala Lumpur, Malaysia, are 452 meters tall. A woman who is 1.75 meters tall stands 120 meters from the b

bazaltina [42]

Answer:

$75.1^{\circ}$

Step-by-step explanation:

In this problem, we have:

H = 452 m is the height of the Petronas tower

h = 1.75 m is the height of the woman

d = 120 m is the distance between the woman and the base of the tower

First of all, we notice that we want to find the angle of elevation between the woman's hat the top of the tower; this means that we have consider the difference between the height of the tower and the height of the woman, so

$H' = H-h = 452-1.75=450.25 m$

Now we notice that $d$ and $H'$ are the two sides of a right triangle, in which the angle of elevation is $\theta$ . Therefore, we can write the following relationship:

$tan \theta = \frac{H'}{d}$

since

H' represents the side of the triangle opposite to $\theta$

d represents the side of the triangle adjacent to $\theta$

Solving the equation for $\theta$ , we find the angle of elevation:

$\theta = tan^{-1}(\frac{H'}{d})=tan^{-1}(\frac{450.25}{120})=75.1^{\circ}$

3 0

3 years ago

Will Mark Brainlest Help Please ,,,,

insens350 [35]

$\\ \sf\longmapsto 2x+y=2$

$\\ \sf\longmapsto 2x=2-y$

$\\ \sf\longmapsto x=\dfrac{2-y}{2}\dots(1)$

And

$\\ \sf\longmapsto x+1=y+2$

$\\ \sf\longmapsto x=y+2-1$

$\\ \sf\longmapsto x=y+1$

Put the value

$\\ \sf\longmapsto \dfrac{2-y}{2}=y+1$

$\\ \sf\longmapsto 2-y=2(y+1)$

$\\ \sf\longmapsto 2-y=2y+2$

$\\ \sf\longmapsto 2-2=2y+y$

$\\ \sf\longmapsto 3y=0$

$\\ \sf\longmapsto y=\dfrac{0}{3}$

$\\ \sf\longmapsto y=\infty$

Put in eq(1)

$\\ \sf\longmapsto x=\dfrac{2-y}{2}$

$\\ \sf\longmapsto x=\dfrac{2-\infty}{2}$

$\\ \sf\longmapsto x=\dfrac{2}{2}$

$\\ \sf\longmapsto x=1$

5 0

3 years ago

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