Answer:
in 13 years it will be at 432,480
Step-by-step explanation:
Answer:
<u>2,365,200,000 times</u>
Step-by-step explanation:
<u>Given</u> :
- Average heartbeat rate = 60 times/minute
- Avg. human lifespan = 75 years
<u>To Find</u> :
- Number of heartbeats in lifetime of 75 years
<u>Solving</u> :
- Let the number we require be n
- n = average heartbeat rate x 60 x 24 x 365 x 75
- n = 60 x 60 x 24 x 365 x 75
- n = 3600 x 24 x 365 x 75
- n = 86400 x 365 x 75
- n = 31536000 x 75
- n = <u>2,365,200,000 times</u>
Answer:
a) H0: p > 0.0016
H1: p ≤ 0.0016
Step-by-step explanation:
A null hypothesis states that there is no relation between two variables, it's what the researcher wants to discredit.
On the other hand, the alternative hypothesis is what the researcher tries to prove.
<u>The claim of this entomologists is that fewer than 16 in ten thousand male fireflies are unable to produce light due to a genetic mutation. Therefore, this claim is what he wants to prove and it would be the alternative hypothesis.</u>
H1: p ≤ 0.0016
The null hypothesis would be the opposite of the alternative hypothesis and therefore it would be:
H0: p > 0.0016
First take note he only has $20 and the bag he must buy is $12.55. Also the loose seeds are $1.49 per pound.
To solve subtract 12.55 from 20
20-12.55=7.45
So after buying the 10 lb bag he has $7.45 left now divide that by 1.49
7.45/1.49=5
So after buying the 10 lb bag he can also buy 5 lb of the loose seeds!
The first term is 138
The difference is 55
The iterative rule for the amount of money Mr Speas has after n weeks is
55/2 n² + 221/2 n
During the first week she has $138 in his bank account. At the end of each week she deposited $55 into her bank account.
The first term will be 138 .
The common difference is 55 because her bank always increase by $55 dollars every week. The sequence will be 138, 193, 248, 303, 358...…
The difference = 193 - 138 = 55.
The iterative rule for the amount of money Mr Speas has after n weeks can be represented below
n = number of weeks
a = first term = 138
d = common difference = 55
Using AP formula,
sₙ = n/2(2a + (n - 1)d)
sₙ = n/2 (2(138)+ (n - 1)55)
sₙ = n /2(276 + 55n -55)
sₙ = n /2(221 + 55n)
sₙ = 55/2 n² + 221/2 n
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