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Alex_Xolod [135]
3 years ago
14

What is the value of 3 in 630 is it hundred ten or ones

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0
The value of 3 in 630 is ten
mihalych1998 [28]3 years ago
3 0
The value of 3 in 630 is 30
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20 POINTS!!!
Anestetic [448]
Only b because A is correct
3 0
2 years ago
I am soooo confuseddd what the heckkk Ok so Im doing something called 'Graphing Systems of Linear Equations' , well you might sa
horsena [70]
Okay, so the equation for the y-intercept is y=mx+b, this will be your base for graphing anything.

For y = x + 3 it's basically y = 1x + 3. Use b as the y-intercept, or 3, and plot it as (x,y), (0,3). Then use m as the slope, or 1. 1 means positive one so the point goes (0,3), (1, 4), (2, 5).

For y = -3x - 1 it's the same thing but different numbers. Use b, the y-intercept, and plot it. -1 is b, so plot (0,-1). Then use the slope to go up or down the direction you need to go, or m. m is -3, so for every +1 in x, the y will decrease by 3. (0,-1), (0,-4), (0,-7).

I hope this helped in some way or increased your understanding!
4 0
2 years ago
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
The data shows the number of customers Joe's Diner served during lunchtime hours for the past 12 days. 22, 25, 50, 58, 28, 24, 2
timofeeve [1]

Answer:

Boxplot A

Step-by-step explanation:

Given the data:

22, 25, 50, 58, 28, 24, 25, 51, 43, 32, 49, 38

We should obtain the 5 number summary and check which boxplot correctly displays the information :

Reordered data : 22, 24, 25, 25, 28, 32, 38, 43, 49, 50, 51, 58

. Maximum = 58

Minimum = 22

Lower quartile : 1/4(n+1)th term

n = 12

1/4(13)th term = 3.25

(3rd + 4th) = (25 + 25) /2 = 25

Median :

1/2(13)th = 6.5th term

(32 + 38) /2 = 35

Upper quartile :

3/4(13)th term 9.75 term

(49 + 50) / 2

= 49.5

5 0
3 years ago
61:3 odds pays out how much if you bet $25. I think $1550
Sonbull [250]

Answer:

$508.33

Step-by-step explanation:

If I bet $25 (And I win, of course), I will win:

If I win $61 per every $3 bet, then:

61/3 = x/25 ⇒ Solving for 'x':

61*25/3 = $508.33

Finally, if you bet $25 you will win $508.33.

4 0
3 years ago
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