All categories

3 years ago

Find the radius of a circle in which an inscribed square has a side of 8 inches

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

I hope this help you I gess 16

You might be interested in

How would you solve this without a calculator?

Soloha48 [4]

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Exact Form:

$1351+780\sqrt{3}$

Decimal Form:

2701.99962990

Thus, 2,701 is your answer

5 0

1 year ago

1/9 and 1/8 closer to 0,0.5 or 1

pentagon [3]

Answer;

they are both closer to 0

Step-by-step explanation:

9/9= 1

4/9= approximately 0.5

8/8= 1

4/8= 0.5

6 0

2 years ago

Select the correct answer.

Alex_Xolod [135]

The answer is D

Explanation:

3 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Solved

6 0

2 years ago

How do I answer this?

Stels [109]

If you are trying to find the area the answer would be 48

3 0

2 years ago