Given:
Rolling a fair dice.
To find:
The theoretical probability of rolling a number less than 5.
Solution:
The possible numbers of rolling a dice are 1, 2, 3, 4, 5, 6.
Total outcomes = 6
Numbers less than 5 are 1, 2, 3, 4.
Favorable outcomes = 4
Now, the theoretical probability of rolling a number less than 5 is:
In decimal form, it can be written as:
In percentage form, it can be written as:
Therefore, the theoretical probability of rolling a number less than 5 in the fraction, decimal and percent are 
and 
respectively.
X1 + x2 / 2 , y1 + y2 / 2
8 + x2 /2 = 6
So x is 4
9 + y2 /2 = 6
So y is 3.
Answer is B ( 4, 3)
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(12x^2y^−2)^5(4xy^-3)^−7
= (248832x^10y^21)/(16384x^7y^10)
= (248832x^3y^11)/(16384)
= (243x^3y^11)/16
Answer:
3×5×53
Step-by-step explanation:
You can use divisibility rules to find the small prime factors.
The number ends in 5, so is divisible by 5.
795/5 = 159
The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.
159/3 = 53 . . . . . a prime number,* so we're done.
795 = 3×5×53
_____
* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.
