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xz_007 [3.2K]
3 years ago
8

Douglas is placing strings of lights around the edge of a circular patio with a diameter of 7.5 meters. The lights are in length

s of 1.45 meters. What is the best approximation for how many strings of lights Douglas needs? HURRY I WILL BRAINLIEST!!!!!!!
Mathematics
2 answers:
Mrac [35]3 years ago
8 0
So first you need the find the circumference 
which is the diameter multiply pi (simplified to 3.14)
7.5*3.14=23.55
so divide 23.55 and 1.45
which is this painfully long number
16.2413793103
but you should round UP because its fine to have more than not enough
so about 17

OLEGan [10]3 years ago
4 0
<span>17 is the correct answer hope this helps, and have a nice day</span>
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Help and explain this to me
JulsSmile [24]
5.5(7.5 + x)

Multiply 7.5 and x by 5.5.

41.25 + 5.5x

41.25 is the area of the blue part of the mural, and 5.5x is the area of the red part of the mural.
3 0
3 years ago
5+5= plz help have to be complete awnser and i will give you crown
Black_prince [1.1K]

Answer:

it is 10

Step-by-step explanation:

because you can switch like 5x2 or 5+5

3 0
3 years ago
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Does anyone know????
Temka [501]

Answer: x + y

Step-by-step explanation: I think that’s it, not too good with that stuff, sorry

5 0
3 years ago
A cardboard sheet is cut in the shape of a triangle, with vertices at (0,0), (20,0), and (3,4) units. the thickness of the sheet
kenny6666 [7]
This problem can be solved in two ways, the long way, or the short way.

1. The long way
We know that the base of the triangle is along the x-axis, and the length of the base is 20.
The centre of mass is located at 2/3 of the distance from vertex (3,4) along the median, which cuts the base at (10,0).
Therefore the centre of mass is located at
x=3+(10-3)*2/3=23/3
y=4/3

2. The short way
It turns out that the centre of mass of a triangle sheet is located at the mean of the coordinates of the three vertices, i.e.
CG=((0+20+3)/3, (0+0+4)/3)=(23/3, 4/3)  as before.
6 0
3 years ago
I need help with number #11
nikklg [1K]

Answer:

KJFJDSKLJDKLFJDSKJDSFKDMF;DS MDF NM FDSF DS FSDFSD FJJKFSDN DSF DSJFJDSFDNFDFNDMFDNSAFJASNF,MASFNAS2`1849 ,MNFNMADBFASBJ2L31U93O2KQN 4Y72 7IW4N LOOK THIS UP TO GET ANSWERS

Step-by-step explanation:

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