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soldi70 [24.7K]
3 years ago
14

The number of limbs on a 2 year old oak tree is 21. is this discrete or continuous data?

Mathematics
2 answers:
Aleks04 [339]3 years ago
8 0
Continuous because it has something to do with the tree itself.
ValentinkaMS [17]3 years ago
5 0
It is discrete data if there is a 2 year old oak tree then it has 21 limbs

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I need help with this question asap
Nataly_w [17]

Answer:

The correct answer would be the bottom equation.

Step-by-step explanation:

y=7.25x

y=7.25(3)

y=21.75

y=7.25(4)

y=29.00

y=7.25(5)

y=36.25

7 0
3 years ago
What if i=radical -1, what is the value of i^3
aleksklad [387]

\bf i^3\implies \sqrt{-1}\cdot \sqrt{-1}\cdot \sqrt{-1}\implies (\sqrt{-1})^2\sqrt{-1}\implies \sqrt{(-1)^2}\cdot \sqrt{-1} \\\\\\ -1\cdot i\implies \boxed{-i}

6 0
3 years ago
Evaluate 5+\left(-3\right)-65+(−3)−65, plus, left parenthesis, minus, 3, right parenthesis, minus, 6.
Serga [27]

The question is not well-expressed, but it looks like you want to evaluate

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

Answer:

-140

Step-by-step explanation:

First of all, note the following

- Multiplying a negative number by another negative number gives a positive number.

- Multiplying a negative number by a positive number gives a negative number.

- Multiplying a positive number by a positive number gives a positive number.

- Brackets mean multiplication.

So

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

= 5 - 3 - 65 - 3 - 65 - 3 - 6

= -140

7 0
3 years ago
(3t + 7)−2(6.3t + 4) *<br><br> 15.6t − 1<br> 15.6t + 15<br> −9.6t + 15<br> −9.6t - 1
vodka [1.7K]

Answer:the anser is -9.6t-1

Step-by-step explanation:

8 0
3 years ago
Taylor dropped a rubber ball from a height of 8 feet.The ball hit the ground after 1 second,bounced up to 5 feet in the next sec
Rzqust [24]

Answer:

The graph is constant in the interval [4,6]

Step-by-step explanation:

We are given that,

Taylor dropped a rubber ball from a height of 8 feet.

So, at time t= 0 sec, the ball is being thrown.

Now, the next events follows as below:

1. After a second, the ball hits the ground.

2. It bounces up to 5 feet in the next second.

3. The ball again hits the ground in the next second.

4. Now, the ball again jumps up to height 2.5 feet, when Taylor holds the ball for 2 seconds more.

So, we get the figure given below, we see that,

The graph is constant in the interval [4,6].

3 0
3 years ago
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