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Anettt [7]
3 years ago
11

What if i=radical -1, what is the value of i^3

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

\bf i^3\implies \sqrt{-1}\cdot \sqrt{-1}\cdot \sqrt{-1}\implies (\sqrt{-1})^2\sqrt{-1}\implies \sqrt{(-1)^2}\cdot \sqrt{-1} \\\\\\ -1\cdot i\implies \boxed{-i}

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For how many tickets is the cost the same for club members and nonmembers? Club members = $30 one time fee and $3 per ticket
WARRIOR [948]
There would have to be one non club member, and 2 club members who bought the tickets.
6 0
3 years ago
Please answer!!!! please!!!!!!
olga55 [171]

The problem here is:  Too many words.

If you boil the problem down to the bare facts, the question is:

             "$210 is 15% of what number ?"

I'm pretty sure you can take it from there,
but here's the rest of it anyway:

                                                $210  =  15% of (March amount)

                                                $210  =  0.15 x (March amount)

Divide each side by  0.15 :     $1400 = March amount .

Check:
1400 + 210 =  1610
1.15 x 1400 = 1610                                      yay!
5 0
3 years ago
How many solutions does the following equation have?
IrinaK [193]
Answer:
Exactly one solution

Explanation:
The first step we need to take to find the answer is to find the value of y.

7(y+3)=5y+8
Expand the parentheses
7y+21=5y+8
Subtract both sides by 21
7y+21-21=5y+8-21
7y=5y-13
Subtract both sides by 5y
7y-5y=5y-13-5y
2y=-13
Divide both sides by 2
2y/2=-13/2
y=-6.5

Now, we plug y back into the original equation.

7(y+3)=5y+8
7(-6.5+3)=5(-6.5)+8
Expand the parentheses
-45.5+21=-32.5+8
-24.5=-24.5

Because both sides of the equation is equal and the equation is true, we can conclude that the equation has one solution.

I hope this helps!
7 0
3 years ago
Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

4 0
3 years ago
Read 2 more answers
If the width of a rectangle is x + 2 and the length is twice as long, what is the area?
lawyer [7]
A=(x+2)(2(x+2)=(x+2)(2x+4)=2x^2+4x+4x+8=\\
=x^2+8x+8
4 0
3 years ago
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