Answer:
x = 3.6
B. {7.88}
Step-by-step explanation:

x · 10 = 6 · 6
10x = 36
10x ÷ 10 = 36 ÷ 10
x = 3.6

8 · x = 9 · 7
8x = 63
8x ÷ 8 = 63 ÷ 8
or x = 7.875
7.875 rounded to the nearest tenth is 7.88.
For this case we have the following expression:

We follow the steps below:
We subtract 4x on both sides of the equation:

We subtract 10 from both sides of the equation:

Now, we must complete squares.
When we have an equation of the form:
, if we want to complete squares we must subtract c on both sides of the equation obtaining:

The square is completed by adding to both sides of the equation: 
So, we have left:

In the given expression we have:

And to complete the square we have:

Rewriting we have:

We factor the left side of the equation, that is, we look for two numbers that when added together result in -8 and when multiplied as a result 16. We have:

So, we have:

Answer:
The intermediate step is to complete squares

Answer:
A. y = -x -2
Step-by-step explanation:
thanks for the questions.
Answer:
40
Step-by-step explanation:
Do 60 × 10.00 to get 600. Then do 800-600 to get 200. Then do 200÷5.00 to get 40.
Answer:
y = - 2x + (1/2 38) + 2 = y = -2x + 19x + 2 at any second and y = -2x^2 / 2 + 19/2 + 2/2 = <u>- x^2 + 19/2 + 2 </u>= - x (4) + 19/2(4) + 1 = -4+ 38 + 1 = 35 seconds
Step-by-step explanation: We see that 38-2ft = 36ft and y intercept = 2 and then -2x allows us to represent the starting point 2 as -2 (1) to allow a descend to our back to 0 for y one we find y intercept we know - x^2 is our simplified equation and an input into this to find the static and slowed descend back to 0 if you keep inputting at 5 and 6 you see the equation speed up Anyway at (4) substitute = 4 seconds we divide our simplified equation a = -x2 into a b c and divide each by 2 before working out the<u> </u><u>decline</u> of the equation<u> (as equation still represents all ascending and descending) </u>for the 4th second as the height was <u>already said to be at its max at 38 feet see equation in answer to find 4 as substitute for x </u>