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Ratling [72]
3 years ago
11

All exothermic reactions _____. Select all that apply. a. are endothermic b. are exothermic c.release energy d.are rapid reactio

ns help me fast
im giving 98 pts
Chemistry
2 answers:
VashaNatasha [74]3 years ago
7 0

Answer:

All exothermic reactions _c.release energy____

Explanation:

Paha777 [63]3 years ago
4 0

Answer:

All exothermic reactions _c.release energy____

Explanation:

Exothermic reactions are those that give off energy, for example in the form of heat in combustion (it has a negative enthalpy variation, the energy of the products being less than the energy of the reagents)

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An emulsifying agent is typically characterized by having
pochemuha

The third substance or agent which produce the film between the interface of two immiscible liquids and thus stabilize the system are known as an emulsifying agent.

Since the solubility of the liquids depends on the polarity of the mixing liquids the thumb rule of solubility is like dissolves like that means polar liquid dissolves in polar liquid only and vice versa. For two immiscible liquids, the emulsifying agent is used which does not chemically change the polarity of liquids but acts as bridge between immiscible liquids, the polar end of the emulsifier attach to the polar liquid and the non-polar end of the emulsifier attach to the non-polar end and thus help in dissolving.

Therefore, the one end of the emulsifier is polar and the other end is non-polar

5 0
4 years ago
Joseph Proust showed that when elements combine to form new substances, they do so in specific mass ratios.a) trueb) false
olga55 [171]

Answer: option A) True

Explanation:

Joseph Proust is the founder of the Law of Definite proportion. This law states that two elements will always combine together to form a chemical compound and this will be in the same proportion by mass.

For Example: 2 moles of Hydrogen (H2) ALWAYS combine with 1 atom of Oxygen (O) to yield water (H2O)

So, the answer is True

3 0
3 years ago
PLEASE ANSWER ASAP AND SHOW WORK: A camping stove uses a 5.0 L propane tank that holds 68.0 moles of liquid C3H8. How large a co
seropon [69]

<u>Answer:</u> The volume of the container needed is 554.6 L

<u>Explanation:</u>

To calculate the volume of the gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 3.0 atm

V = Volume of the gas = ? L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles of propane gas = 68.0 moles

Putting values in above equation, we get:

3.0atm\times ?L=68mol\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{68\times 0.0821\times 298}{3.0}=554.6L

Hence, the volume of the container needed is 554.6 L

6 0
3 years ago
How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?
Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

4 0
3 years ago
Which skill involves creating representation of complex objects or processes
lesya692 [45]

Answer:

Making models

Explanation:

Classifying is the grouping together of items that are alike in some way. Answer: Making models involves creating rep- resentations of complex objects or processes.

6 0
3 years ago
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