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kogti [31]
3 years ago
14

If a gas is cooled from 315K to 231K and the volume is kept constant, what would the final pressure be if the original pressure

was 621 mmHg ?
Chemistry
1 answer:
goblinko [34]3 years ago
5 0

Answer:

455.4 mmHg

Explanation:

To solve this problem we can use <em>Gay Lussac's Law</em>, which describe the temperature and pressure of a gas, at constant volume and composition:

  • P₁T₂ =  P₂T₁

In this case:

  • P₁ = 621 mmHg
  • P₂ = ?
  • T₁ = 315 K
  • T₂ = 231 K

We <u>input the data</u>:

  • 621 mmHg * 231 K = P₂ * 315 K

And <u>solve for P₂</u>:

  • P₂ = 455.4 mmHg
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Georgia [21]
Use M1V1 = M2V2 to solve
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3 years ago
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Directions: Each set of lettered choices below refers to the numbered statements immediately following it. Select the one letter
maksim [4K]

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Explanation :

Disproportionation reaction : It is defined as the reaction in which the same reactant undergoes both oxidation and reduction reaction. It is a redox reaction.

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

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Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(A) The given balanced reaction is,

H_2SeO_4(aq)+2Cl^-(aq)+2H^+(aq)\rightarrow H_2SeO_3(aq)+Cl_2(g)+H_2O(l)

This reaction is a redox reaction but not disproportionation reaction because in this reaction there are two reactants in which chlorine shows oxidation and selenium shows reduction.

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This reaction is a redox reaction but not disproportionation reaction because in this reaction there are two reactants in which sulfur shows oxidation and oxygen shows reduction.

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3Br_2(aq)+6OH^-(aq)\rightarrow 5Br^-(aq)+BrO_3^-(aq)+3H_2O(l)

This reaction is a disproportionation reaction because in this reaction only one reactant bromine that shows both oxidation and reduction reaction.

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Ca^{2+}(aq)+SO_4^{2-}(aq)\rightarrow CaSO_4(s)

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PtCl_4(s)+2Cl^-(aq)\rightarrow PtCl_6^{2-}(aq)

This reaction is a combination reaction in which the two reactant react to give a single product. There is no changes in the oxidation state of platinum and chlorine.

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Explanation :

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agasfer [191]
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Answer:

see explanation below

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Question is incomplete, so in picture 1, you have a sample of this question with the missing data.

Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

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