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ElenaW [278]
3 years ago
10

Can someone help me? -just check my latest question.. thanks... ​

Chemistry
1 answer:
Harman [31]3 years ago
7 0

Explanation:

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<h2>yes can you. do this</h2>
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A blank is a condition that strays from normal homeostasis.
AURORKA [14]

homeostatic imbalance is the answer, because it's when the internal environment cannot remain in equilibrium.

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3 years ago
The average kinetic energy of the particles in an object is directly proportional to its
Galina-37 [17]
C. Temperature the average <span> kinetic energy of the particles in an object is directly proportional to its temperature </span>
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3 years ago
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The ka for hcn is 4.9 ⋅ 10-10. What is the value of kb for cn-?
marusya05 [52]

Answer:

kb = 2,0x10⁻⁵

Explanation:

The ka for HCN is:

HCN ⇄ H⁺ + CN⁻; ka = 4,9x10⁻¹⁰ <em>(1)</em>

The inverse reaction has an equilibrium constant of:

H⁺ + CN⁻ ⇄ HCN k = 1/4,9x10⁻¹⁰ = 2,0x10⁹ <em>(2)</em>

As the equilibrium of the water is:

H₂O ⇄ H⁺ + OH⁻; kw = 1x10⁻¹⁴ <em>(3)</em>

The sum of (2) + (3) gives:

H₂O + CN⁻ ⇄ HCN + OH⁻; kb = kw×k = 1x10⁻¹⁴×2,0x10⁹ =

2,0x10⁻⁶; <em>kb = 2,0x10⁻⁵</em>

<em />

<em>-In fact, the general formula to convert from ka to kb is:</em>

<em>kb = kw / ka-</em>

<em />

I hope it helps!

5 0
3 years ago
At a birthday pool party, the temperature is 28.50°C and the atmospheric pressure is 755.4 mmHg. One of the decoration helium ba
Iteru [2.4K]

Answer:

The volume of the balloon will be 5.11L

Explanation:

An excersise to solve with the Ideal Gases Law

First of all, let's convert the pressure in mmHg to atm

1 atm = 760 mmHg

760 mmHg ___ 1 atm

755.4 mmHg ____ (755.4 / 760) = 0.993 atm

922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm

T° in K = 273 + °C

28.5 °C +273 = 301.5K

26.35°C + 273= 299.35K

P . V = n . R .T

First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K

(0.993atm . 6.25L) / 0.082 . 301.5 = n

0.251 moles = n

Second situation:

1.214 atm . V = 0.251 moles . 0.082 . 301.5K

V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm

V = 5.11L

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3 years ago
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How many moles of neon gas are there 25.0 L of gas or 5.0°C with a pressure of 89.9 KPa?
vladimir2022 [97]
  • Volume=25L
  • Temperature=5°C
  • Pressure=89.9kPa

Now

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{89.9(25)}{5R}

\\ \rm\rightarrowtail n=89.9(5)/R

\\ \rm\rightarrowtail n=449.5/R mol

8 0
2 years ago
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