Answer:
The answer is 0.046 mol.
Explanation:
By looking at the balanced equation, you can form a ratio of lithium chloride and lithium bromide using the coefficient value :
ratio of lithium bromide <u>(</u>2LiBr)
= 2
ratio of lithium chloride (2LiCl)
= 2
So the ratio is 2 : 2 then simplify into 1 : 1 . Which means that 1 mol of lithium bromide is equal to 1 mole of lithium chloride.
In this case, 0.046 mol of lithium bromide will form <u>0</u><u>.</u><u>0</u><u>4</u><u>6</u><u> </u><u>m</u><u>o</u><u>l</u> of lithium chloride.
When the substance is said to be an oxide of iron, that means the compound contains elements of Fe and O. Suppose you have 100 g of the sample.
Mass of Fe = 72.36 g
Mass of O = 100 - 72.36 = 27.64 g
The molar mass of Fe is 55.8 g/mol while the molar mass of O is 16 g/mol.
Moles of Fe = 72.36/55.8 = 1.29677
Moles of O = 27.64/16 = 1.7275
Now, divide both amounts by the lower number, which is 1.29677.
Fe: 1.29677/1.29677 = 1
O = 1.7275/1.29677 = 1.333
The answer must be whole numbers. So, let's try multiplying the least number to O that would make it a whole number. That would be 3.
Fe: 1*3 = 3
O: 1.333*3 = 4
<em>Thus, the empirical formula is Fe₃O₄.</em>