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1 year ago

Which process in the nitrogen cycle converts nitrogen into its most polluting form?

Chemistry

1 answer:

Ira Lisetskai [31]1 year ago

4 0

The process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".

The biological process of nitrification turns ammonia into nitrite and nitrite into nitrate. The technique of denitrification, which turns nitrate into nitrogen gas, is such treatment option if requirements demand that the resultant nitrate be eliminated.

A surplus of nitrogen compounds could result in pollutants like ammonia and ozone that can affect plant growth, visibility, and human capacity to breathe. Excess nitrogen from the atmosphere that returns to earth could be damaging to the health of forests, soils, including streams.

Therefore, the process in the nitrogen cycle converts nitrogen into its most polluting form will be "nitrification".

To know more about nitrogen cycle

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Element A has an electronegativity of 0.8 and element B has an electronegativity of 3.0. Which statement best describes the bond

Advocard [28]

Answer:

C) The compound is largely ionic with A as the cation.

Explanation:

Pulings proposed the method to determine if the compound is ionic in nature or covalent in nature , by finding the difference between the electronegativity of the respective cation and anion .

The ion with higher electronegativity is the anion and the ion with lower electronegativity is the cation.

The electronegativity difference above 1.7 make the compound ionic in nature.

Hence, from the question ,

A is the cation and B is the anion.

And the electronegativity difference above 1.7 so the compound is ionic in nature.

8 0

3 years ago

Define weak force and strong force pls need it thanks so much :) :)

Semmy [17]

In particles physics, the weak interaction (the weak force or weak nuclear force) is one of the four known fundamentals interactions of nature, alongside the strong interaction, electromagnetism, and gravitation.

This is based on my research, hope it helped :) <span />

6 0

3 years ago

Which property could allow a student to easily separate sand and iron filings? (1 point,

Artist 52 [7]

Magnetic separation is a method that uses magnetic force to remove the magnetically sensitive material from a mixture. Because iron is attracted by magnets, this is the ideal method for separating sand and iron fillings.

Magnetism was the physical attribute that allowed this combination to be separated. I used the magnet to separate the iron filing from the sand in the mixture. The magnet attracted the iron filings but not the sand. We were able to separate the iron filings from the sand as a result of this.

Because iron is magnetic while the other two are not, a magnet may be used to pull the iron filings out of the mixture while leaving the salt and sand. Sand is not water-soluble, although salt is. This implies they may be combined in water and swirled together. The salt dissolves, but the sand does not.

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5 0

1 year ago

When the reaction CO2(g) + H2(g) ⇄ H2O(g) + CO(g) is at equilibrium at 1800◦C, the equilibrium concentrations are found to be [C

UNO [17]

Answer:

The new molar concentration of CO at equilibrium will be :[CO]=1.16 M.

Explanation:

Equilibrium concentration of all reactant and product:

$[CO_2] = 0.24 M, [H_2] = 0.24 M, [H_2O] = 0.48 M, [CO] = 0.48 M$

Equilibrium constant of the reaction :

$K=\frac{[H_2O][CO]}{[CO_2][H_2]}=\frac{0.48 M\times 0.48 M}{0.24 M\times 0.24 M}$

K = 4

$CO_2(g) + H_2(g) \rightleftharpoons H_2O(g) + CO(g)$

Concentration at eq'm:

0.24 M 0.24 M 0.48 M 0.48 M

After addition of 0.34 moles per liter of $CO_2$ and $H_2$ are added.

(0.24+0.34) M (0.24+0.34) M (0.48+x)M (0.48+x)M

Equilibrium constant of the reaction after addition of more carbon dioxide and water:

$K=4=\frac{(0.48+x)M\times (0.48+x)M}{(0.24+0.34)\times (0.24+0.34) M}$

$4=\frac{(0.48+x)^2}{(0.24+0.34)^2}$

Solving for x: x = 0.68

The new molar concentration of CO at equilibrium will be:

[CO]= (0.48+x)M = (0.48+0.68 )M = 1.16 M

3 0

3 years ago

A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 198 picometers and its

Neko [114]

Answer:

7.38 g/cm³ is the density of the metal

Explanation:

In a Face-centered cubic unit cell you have 4 atoms. Also, the edge length is √8×r (r is radius of the atom).

To solve this problem, we need first to calculate the volume of the unit cell and then, with molar mass calculate the mass of 4 atoms. As density is the ratio between mass and volume we can obtain this value.

<em>Volume of the unit cell</em>

Volume = a³

a = √8×r

(r = 198x10⁻¹²m)

a = 5.6x10⁻¹⁰ m

Volume = 1.756x10⁻²⁸ m³

1m = 100cm → 1m³ = (100cm)³:

1.756x10⁻²⁸ m³× ((100cm)³ / 1m³) =

<h3> 1.756x10⁻²² cm³ → Volume of the unit cell in cm³</h3><h3 />

<em>Mass of the unit cell:</em>

<em>There are 4 atoms of gold:</em>

4 atoms × (1mol / 6.022x10²³ atoms) = 6.64x10⁻²⁴ moles of gold

As 1 mole weighs 195.08g:

6.64x10⁻²⁴ moles of gold × (195.08g / mol) =

<em>Density of the metal:</em>

1.296x10⁻²¹g / 1.756x10⁻²² cm³ =

<h3>7.38 g/cm³ is the density of the metal</h3>

3 0

2 years ago