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Allisa [31]
3 years ago
9

In Dante Controller’s Clock Status tab, you see reports of more than one clock master. The Dante Controller Log also shows devic

es reporting sync loss occasionally. What steps would you take to find the root cause of the problem?
Physics
1 answer:
jeka943 years ago
6 0

Answer:

#See solution for details

Explanation:

-Check theswitch configurations for any evidence of the ACLs being configured. Confirm that all PTP traffic can traverse the network in both directions to all switches. Specifically, UDP ports 319 and 320 on 224.0.1.129

-If IGMP snooping is enabled, test the system with no audio and IGMP snooping turned off. If this resolves the problem, you carefully examine the IGMP snooping configuration in each switch and ensure that they follow the guidelines.

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A piano tuner sounds two strings simultaneously. One has been previously tuned to vibrate at 293.0 Hz. The tuner hears 3.0 beats
ololo11 [35]

Answer:

Part a)

f_B = 290 Hz

Part B)

percentage increase is

percentage = 1.38%

Explanation:

Part a)

As we know that the beat frequency is

f_A - f_B = 3

after increasing the tension the beat frequency is decreased and hence the tension in string B will increase

So we have

293 - f_B = 3

f_B = 290 Hz

Part B)

percentage increase in the tension of the string will be given as

f_A - f_B' = 1

f_B' = 292 Hz

now we have

f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

so we have

T_1 = C (290)^2

T_2 = C(292)^2

so we have

\frac{\Delta T}{T} = \frac{292^2 - 290^2}{290^2}

percentage increase is

percentage = 1.38

4 0
4 years ago
block of mass 0.5kg on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 50N/m . Th
Alisiya [41]

Answer:

Explanation:

The mass of the block is 0.5kg

m = 0.5kg.

The spring constant is 50N/m

k =50N/m.

When the spring is stretch to 0.3m

e=0.3m

The spring oscillates from -0.3 to 0.3m

Therefore, amplitude is A=0.3m

Magnitude of acceleration and the direction of the force

The angular frequency (ω) is given as

ω = √(k/m)

ω = √(50/0.5)

ω = √100

ω = 10rad/s

The acceleration of a SHM is given as

a = -ω²A

a = -10²×0.3

a = -30m/s²

Since we need the magnitude of the acceleration,

Then, a = 30m/s²

To know the direction of net force let apply newtons second law

ΣFnet = ma

Fnet = 0.5 × -30

Fnet = -15N

Fnet = -15•i N

The net force is directed to the negative direction of the x -axis

8 0
4 years ago
Which element is found in group 17 and period 2
exis [7]
The answer is fluorine
4 0
3 years ago
Which instrument is not used to measure air pressure
Virty [35]
It would be b. anemometer. it measures the speed of wind or any current of gas.
5 0
3 years ago
Explain how that energy converts itself from POTENTIAL to KINETIC energy.​
Karolina [17]

Answer:

Potential energy can transfer into other forms of energy like kinetic energy. Kinetic energy is energy an object has because of its motion.

Explanation:

The ball was released, as the ball moves faster and faster toward the ground, the force of gravity will transfer the potential energy to kinetic energy.

8 0
3 years ago
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