Four objects are situated along the y axis as follows: a 2.09-kg object is at +2.97 m, a 2.93-kg object is at +2.53 m, a 2.57-kg object is at the origin, and a 3.92-kg object is at -0.496 m. Where is the center of mass of these objects?
1 answer:
Answer:
x = 0 m
y = 1.02 m
Explanation:
M1 = 2.09 kg
y1 = 2.97 m
M2 = 2.93 kg
y2 = 2.53 m
M3 = 2.57 kg
y3 = 0 m
M4 = 3.92 kg
y5 = -0.496 m
since all objects are situated on the Y-axis, this means the x coordinate of the center of mass is 0.
To find the y coordinate of the center of mass, we apply the equation below.
sum of moment of the objects about the origin = moment of the total mass of objects about the center of mass
M1.y1 + M2.y2 + M3.y3 + M4.y4 = Mt.Y
(2.09 x 2.97) + (2.93 x 2.53) + (2.57 x 0) + (3.92 x -0.496) = (2.09 + 2.93 + 2.57 + 3.92) Y
11.68 = 11.51 Y
Y = 11.68 / 11.51 = 1.02 m
You might be interested in
The answer is 3 I hope I helped
Answer:
Ruko zara ku ch Time dedo na please
Answer:
Explanation:
given
wavelength of light λ = 479 nm
= 479 x 10⁻⁹ m
the angle
θ = 1.15 / 2 = 0.575°
using
condition for diffraction minimum ,
d sinθ = m λ
for first minimum m = 1
d sinθ = λ
therefore ,
slit width
hence, the width of the slit is equal to
Answer:
GAS, LIQUID, CLOUDS
Explanation:
Water can be in three states: solid, liquid and gas, passing from one to another depending on the pressure and temperature.
In this complementation exercise.
When the water cools down the GAS goes to the LIQUID state, these small drops unite and form the CLOUDS
If the planet earth has no land masses, the idealized zonal
precipitation pattern would likely have regions that are wet in the equator and
there will be more of mid-latitudes if the earth has no land masses at all and
it does not exist.