A refracting telescope has a 1.48 m diameter objective lens with focal length 15.4 m and an eyepiece with focal length 3.28 cm.
1 answer:
Answer:
m = 469.51
Explanation:
Given that,
The diameter of a refracting telescope is 1.48 m
Focal length of the objective lens is 15.4 m
Focal length of an eyepiece is 3.28 cm
We need to find the angular magnification of the telescope. The ratio of focal length of objective lens to the focal length of the eye piece is called angular magnification of the telescope. So,
So, the angular magnification of the telescope is 469.51.
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Answer:
The magnitude of actual velocity is <u>496.67 mph</u> and its direction is <u>51.54° with the x axis in the third quadrant</u>.
Explanation:
Given:
Speed of jumbo jet in southwesterly direction = 550 mph
Velocity of jet stream from west to east direction
First let us draw a vectorial representation of the above velocity vectors.
Consider the south direction as negative y axis and west direction as negative x axis.
From the diagram,
The velocity of the jet can be represented as:
Similarly, the velocity of the stream is,
Now, the vector sum of the above two vectors gives the actual velocity of the aircraft. So, the resultant velocity is given as:
Now, magnitude is given as the square root of sum of the squares of the 'i' and 'j' components. So,
As the horizontal and vertical components of actual velocity negative, the resultant vector makes an angle with the x axis in the third quadrant.
The direction is given as:
Therefore, the magnitude of actual velocity is 496.67 mph and its direction is 51.54° with the x axis in the third quadrant.
