In a parallel circuit, each resistor has:
2 answers:
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Answer:
2.87 km/s
Explanation:
radius of planet, R = 1.74 x 10^6 m
Mass of planet, M = 7.35 x 10^22 kg
height, h = 2.55 x 10^6 m
G = 6.67 x 106-11 Nm^2/kg^2
Use teh formula for acceleration due to gravity
g = 1.62 m/s^2
initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0
Use third equation of motion
0 = v² - 2 x 1.62 x 2.55 x 10^6
v² = 8262000
v = 2874.37 m/s
v = 2.87 km/s
Thus, the initial speed should be 2.87 km/s.
Answer:
H vaporization = 100.0788 kJ/mol
Explanation:
Use clausius clapyron's adaptation for the calculation of Hvap as:
Where,
P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.
R is the gas constant.
T₂ = 823°C
T₁ = 633°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So, the temperature,
T₂ = (823 + 273.15) K = 1096.15 K
T₁ = (633 + 273.15) K = 906.15 K
P₂ = 400.0 torr , P₁ = 40.0 torr
R = 8.314 J/K.mol
Applying in the formula to calculate heat of vaporization as:
Solving for heat of vaporization, we get:
H vaporization = 100078.823 J/mol
Also, 1 J = 10⁻³ kJ
So,
<u>H vaporization = 100.0788 kJ/mol</u>
Answer:
83.33% of the roof area will be occupied by the PV cells
Explanation:
Given the data in the question;
time-averaged lighting requirement = 10 W/m²
the annual average solar irradiance = 150 W/m²
the PV efficiency η = 10% = 0.1
battery charging/discharging efficiency η = 80% = 0.8
we know that; Annual average power to the light = × A
Now, the electrical power delivered by the solar cell battery system will be;
⇒ × A
× η
× η
A
=
× A
× η
× η
Such that;
A =
A
/
× A
× η
× η
A / A
=
/
× η
× η
so we substitute
A / A
= 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]
A / A
= 10 W/m² / 12 W/m²
A / A
= 0.8333
A / A
= (0.8333 × 100)%
A / A
= 83.33%
Therefore, 83.33% of the roof area will be occupied by the PV cells.