Which one of the following formulas is used to find the voltage of a circuit?

1. Na jaką wysokość wzniesie się piłka kopnięta pionowo w górę z prędkością 20 m/s ? 2. Piłka o masie 20 dag spada z wysokości 1

Tresset [83]

Answer:

its gonn abe 23

Explanation:

6 0

3 years ago

Read 2 more answers

Which of the following are thought to be rapidly rotating neutron stars with intense magnetic fields? Choose one answer.a. pulsa

frutty [35]

<h2>Answer: Pulsars</h2>

A <u>pulsar</u> is a neutron star that emits very intense electromagnetic radiation at short and periodic intervals ( rotating really fast) due to its intense magnetic field that induces this emission.

Nevertheless, it is important to note that all pulsars are neutron stars, but not all neutron stars are pulsars.

Let's clarify:

A neutron star, is the name given to the remains of a supernova. In itself it is the result of the gravitational collapse of a massive supergiant star after exhausting the fuel in its core.

Neutron stars have a small size for their very high density and they rotate at a huge speed.

However, the way to know that a pulsar is a neutron star is because of its high rotating speed.

8 0

3 years ago

A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth.

Maksim231197 [3]

Answer:

Explanation:

We shall apply law of conservation of mechanical energy for projectile being thrown .

Total energy on the surface = total energy at height h required

a ) At height h , velocity = .351 x ( 2 GM/R x h )

$\frac{-GM}{R} + \frac{m\times(.351\times\sqrt{2GM})^2 }{2R } = \frac{-GMm}{R+h} + 0$

$\frac{-GMm}{R} +\frac{1}{2}\times \frac{-2GMm}{R} \times0.123=\frac{-GMm}{R+h}$

$\frac{0.877GMm}{R} =\frac{-GMm}{R+h}$

h = .14 R

b )

$\frac{-GM}{R} + \frac{m\times(.351\times2GM) }{2R } = \frac{-GMm}{R+h} + 0$

$\frac{-0.649GMm}{R} = \frac{-GMm}{R+h}$

h = .54 R

c ) least initial mechanical energy required at launch if the projectile is to escape Earth

= GMm / R + 1/2 m (2GM/R)

= 0

5 0

3 years ago

Anybody ? Know how to do this

Nesterboy [21]

Just look at the periodic table and google how to read an element from the periodic table. A picture of a single cell from the table will pop up with arrows of what's what and it will help you answer this in no time! (Brainliest please)

4 0

3 years ago

The position of a particle moving in an xy plane is given by with in meters and t in seconds. In unit-vector notation, calculate

Liula [17]

Answer:

a) r(@2sec) = (6.00i - 106j) m ; b) v = ( 19i - 224t³j) m/sec ; c) a = (24i - 336j) m/sec² ; d) θ = -85.1516°

Explanation:

Correct question statement:

The position r of a particle moving in an xy plane is given by r = (2.00t³ - 5.00t)° + (6.00 -7.00t 4 ) ĵ , with r in meters and t in seconds. In unit-vector notation, calculate (a) r , (b) v , find (c) a for t = 2.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t= 2.00 s?

Given Data:

r = (2t³ - 5t)i + ( 6 - 7t⁴)j ----------------equation (1)

a)

r(@2sec) = (2(2)³ - 5(2))i + ( 6 - 7(2)⁴)j

= (6.00i - 106j) m

b)

By taking derivative of equation 1 once, we get

v(t) = ( 6.00t²-5.00 )i - 28t³j ------------- equation (2)

By putting t = 2sec, we get

v = ( 19i - 224t³j) m/sec

c)

By differentiating equation 1 twice of equation 2 once, we get

a(t) = 12ti - 84t²j

At t = 2 sec, we get

a = (24i - 336j) m/sec²

d)

θ = tan ⁻¹ (-224/19) = -85.1516° or 94.8483°

Answer: θ = -85.1516° it is also equivalent to 274.8484°(counterclockwise from +x-axis), and it is in 4th quadrant.

8 0

3 years ago