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Fynjy0 [20]
3 years ago
6

At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l

eft side of the pivot an adult pushes straight down on the teeter-totter with a force of 151 N. Part A In which direction does the teeter-totter rotate if the adult applies the force at a distance of 3.0 m from the pivot?Part B
In which direction does the teeter-totter rotate if the adult applies the force at a distance of 2.5 m from the pivot?
(clockwise/counterclockwise)
Part C
In which direction does the teeter-totter rotate if the adult applies the force at a distance of 2.0 m from the pivot?
(clockwise/counterclockwise)
Physics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

By convention a negative torque leads to clockwise rotation and a positive torque leads to counterclockwise rotation.

here weight of the child =21kgx9.8m/s2 = 205.8N

the torque exerted by the child Tc = - (1.8)(205.8) = -370.44N-m ,negative sign is inserted because this torque is clockwise and is therefore negative by convention.

torque exerted by adult Ta = 3(151) = 453N , counterclockwise torque.

net torque Tnet = -370.44+453 =82.56N , which is positive means counterclockwise rotation.

b) Ta = 2.5x151 = 377.5N-m

Tnet = -370.44+377.5 = 7.06N-m , positive ,counterclockwise rotation.

c)Ta = 2x151 = 302N-m

Tnet = -370.44+302 = -68.44N-m, negative,clockwise rotation.

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satela [25.4K]

Answer:

0.26087 rad/s

Explanation:

mass of the child (m) = 40 kg

velocity (v) = 3 m/s

distance (r) = 1.5 m

moment of inertia (I) = 600 kg.m^{2}

rotational momentum of the child = Iω

where

  • moment of inertia of the child (I) = mr^{2} = 40 x 1.5 x 1.5 = 90 kg/m^{2}
  • angular velocity (ω) = velocity / distance = 3 / 1.5 = 2 rad/s

rotational momentum of the child = Iω = 90 x 2 = 180 kgm^{2}/s

from the conservation of momentum the initial momentum of the child must be the same as the final momentum of the child

initial momentum of the child = final momentum of the child

180 = (90 + 600) ω

180 = 690 ω

ω = 180 / 690 = 0.26087 rad/s

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3 years ago
How can neptune have more mass than uranus but a smaller diameter?
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Answer:

(1). Going in the order: Gas, Liquid, Solid.

    Particle separation: Very large; large; small.

    Strength of forces between particles: very weak; weak; strong.

(2). a. The change of state is condensation.

     b. The density of the substance is increasing as particles move closer together.  

(3). a. The liquid's temperature decreases until it reaches solidification (freezing) point, and then the temperature will remain constant until all of the liquid has solidified.

     b. The particles move with less and less energy until they have low enough energy to come together and solidify, then they will release more energy when they come together to form bonds, and vibrate about their equilibrium positions once they are part of a  molecular bond.

Additional explanation:

(1). The particle separation in a gas is very large because the gas has a very low density, and since particles are not that close together,<em> the strength of forces between particles is very weak</em>.

The liquid is somewhat more denser than the gas and therefore the particle separation is large but less than that in a gas,<em> The strength of forces between particles is still weak but greater  than in a gas. </em>

Finally, particle separation in a solid is small because the solid is still more denser than the liquid, and the strength of forces between particles is strong because it's these forces that give a solid its rigid shape.

(2). a.The change of state of a substance in which particles slow down and move close together is called condensation.

    b. As the particles move close together, they are occupying less and less volume; therefore, the density is increasing.

(3). The explanation is already given in the answer.

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