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3 years ago

Ninas measurements shown in the table here BEST represent a wave with

Physics

2 answers:

krok68 [10]3 years ago

4 0

it will decrease the frequency. Because the wavelength increases

Finger [1]3 years ago

3 0

They best represent a wave with zero energy and zero amplitude.

There are no measurements shown in a table that accompanies
this question having any amplitude or energy greater than zero.

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NEED HELP ASAP!!!!

podryga [215]

The answer is B
I rhink

6 0

3 years ago

Class II levers like ankles and wheelbarrows are useful because they provide mechanical advantage, by amplifying the input force

marusya05 [52]

Answer:

The solution and the explanation are in the Explanation section.

Explanation:

According to the diagram that is in the attached image, the EFFORT force at point A and the load is at O point. The torque due to weight is:

TA = W * (a * cosθ)

The torque due to effort at C point is:

TC = E * (b * cosθ)

The net torque is equal to 0, we have:

Tnet = 0

W * (a * cosθ) - E * (b * cosθ) = 0

$E=W\frac{a}{b}$

From the figure, you can observe that a/b < 1, thus E < W

8 0

3 years ago

A 3-kg rock is thrown upward with a force of 200 N at a location where the local gravitational acceleration is 9.79 m/s2 . Deter

expeople1 [14]

Answer: $56.87m/s^{2}$

Explanation:

If we make an analysis of the net force $F_{net}$ of the rock that was thrown upwards, we will have the following:

$F_{net}=F_{up}-W$ (1)

Where:

$F_{up}=200N$ is the force with which the rock was thrown

$W$ is the weight of the rock

Being the weight the relation between the mass $m=3kg$ of the rock and the acceleration due gravity $g=9.79m/s^{2}$ :

$W=m.g=(3kg)(9.79m/s^{2})$ (2)

$W=29.37 N$ (3)

Substituting (3) in (1):

$F_{net}=200N-29.37 N$ (4)

$F_{net}=170.63 N$ (5) This is the net Force on the rock

On the other hand, we know this force is equal to the multiplication of the mass with the acceleration, according to Newton's 2nd Law:

$F_{net}=m.a$ (6)

Finding the acceleration $a$ :

$a=\frac{F_{net}}{m}$ (7)

$a=\frac{170.63 N}{3kg}$ (8)

Finally:

$a=56.87m/s^{2}$

3 0

3 years ago

For a top player, a tennis ball may leave the racket on the serve with a speed of 55 m/s (about 120 mi/h). If the ball has a mas

inn [45]

Answer:

Yes is large enough

Explanation:

We need to apply the second Newton's Law to find the solution.

We know that,

$F= ma$

And we know as well that

$a= \frac{v}{t}$

Replacing the aceleration value in the equation force we have,

$F= \frac{mv}{t}$

Substituting our values we have,

$F= \frac{(0.060)(55)}{4*10^{-3}}$

$F=825N$

The weight of the person is then,

$W = mg$

$W = (60)(9.8) = 558N$

<em>We can conclude that force on the ball is large to lift the ball</em>

6 0

3 years ago

A fly travels along the x-axis. His starting point is x = 16 m and his ending point 15x = - 25 m. His flight lasts 4.0 seconds H

gogolik [260]

Explanation:

Starting position at x = 16m

Ending position at x = -25m

Time of flight = 4s

Unknown:

Distance flown = ?

Displacement = ?

Speed = ?

Velocity = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;

So distance = 16 + 25 = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

Speed = $\frac{distance}{time}$ = $\frac{41}{4}$ = 10.25m/s

Velocity is 10.25m/s along -x axis

5 0

2 years ago