Question

Bag A contains 3 white marbles and 2 red marbles. Bag B contains 6 white marbles and 3 red marbles. A person draws one marble from each bag. Find the probability that both marbles are white.
2/5
3/5
9/14

Answer 1

Bag A : 3 white, 2 red....total of 5
Bag B : 6 white, 3 red....total of 9

P(both picks are white) = 3/5 * 6/9 = 18/45 reduces to 2/5 <==

Answer 2

Answer: the probability that both marbles are white = $\dfrac{2}{5}$

Step-by-step explanation:

Given: The number of white marbles in Bag A = 3

Total marbles in Bag A = 5

The probability of drawing white marble from bag A:

$P(A)=\dfrac{3}{5}$

The number of white marbles in Bag B=6

Total marbles in Bag B =9

The probability of drawing white marble from bag B:

$P(B)=\dfrac{6}{9}$

Since both events are independent.

Thus, the probability that both marbles are white:

$P(A)\times P(B)=\dfrac{3}{5}\times\dfrac{6}{9}=\dfrac{2}{5}$