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Svetach [21]
3 years ago
12

Bag A contains 3 white marbles and 2 red marbles. Bag B contains 6 white marbles and 3 red marbles. A person draws one marble fr

om each bag. Find the probability that both marbles are white.
2/5
3/5
9/14
Mathematics
2 answers:
goldenfox [79]3 years ago
8 0
Bag A : 3 white, 2 red....total of 5
Bag B : 6 white, 3 red....total of 9

P(both picks are white) = 3/5 * 6/9 = 18/45 reduces to 2/5 <==
GenaCL600 [577]3 years ago
8 0

Answer: the probability that both marbles are white = \dfrac{2}{5}

Step-by-step explanation:

Given: The number of white marbles in Bag A = 3

Total marbles in Bag A = 5

The probability of drawing white marble from bag A:

P(A)=\dfrac{3}{5}

The number of white marbles in Bag B=6

Total marbles in Bag B =9

The probability of drawing white marble from bag B:

P(B)=\dfrac{6}{9}

Since both events are independent.

Thus, the probability that both marbles are white:

P(A)\times P(B)=\dfrac{3}{5}\times\dfrac{6}{9}=\dfrac{2}{5}

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