Answer:
15.4-4.9=10.5
^ this is what you would do to find what you need to add
10.5+4.9=15.4
I guess-
Answer:
The unit costs are $0.77, $0.62 and $0.27 respectively.
Step-by-step explanation:
The unit price is simply the cost of the items divided by the amount of the items that are included. So, just take the cost and divide it.
$12.29/16 = $0.77 per unit
$19.98/32 = $0.62 per unit
$34.99/128 = $0.27 per unit
Let, Price of a shirt = x
Price of a Jeans = y
Equations would be: 4x + 3y = 150
x + 2y = 70
x = 70-2y
Substitute it into first equation,
4(70-2y) + 3y = 150
280 - 8y + 3y = 150
-5y = -130
y = 130/5
y = 26
Substitute it into 2nd equation,
x + 2(26) = 70
x = 70-52
x = 18
So, Cost of a Shirt = $18 & Cost of a Jeans = $26
Hope this helps!
Hey there.
For 5:
We already have been given all the information we need to solve for this- it's just really extensive, so bare with me here.
With our initial deposit of $150 in January, we give 10% of the current value in the following month. This means 10% of 150 will be deposited into the checking account in February, and so on for the rest. I will work this out.
10% of 150 = 15; we deposit $15 into the account in February.
10% of 165 = 16.5; we deposit $16.5 into the account in March.
10% of 181.5 = 18.15; we deposit $18.15 into the account in April.
10% of 199.65 = 19.965; we deposit $19.96 in May (as we don't have an economical value worth a thousandth of a dollar in this problem).
10% of 219.61 = 21.961; we deposit $21.96 in June.
10% of 241.57 = 24.157; we deposit $24.15 in July.
10% of 265.72 = 26.572; we deposit $26.57 in August.
Our total value is $292.29, although if we added the thousandths, we'd have $292.31; therefore your answer is going to be D.) $292.31
I hope this helps!
Answer:
C
Step-by-step explanation:
We have the system of equations:
And an ordered pair (10, 5).
In order for an ordered pair to satisfy any system of equations, the ordered pair must satisfy both equations.
So, we can eliminate choices A and B. Satisfying only one of the equations does not satisfy the system of equations.
Let’s test the ordered pair. Substituting the values into the first equation, we acquire:
Evaluate:
Evaluate:
So, our ordered pair satisfies the first equation.
Now, we must test it for the second equation. Substituting gives:
Evaluate:
So, the ordered pair does not satisfy the second equation.
Since it does not satisfy both of the equations, the ordered pair is not a solution to the system because it makes at least one of the equations false.
Therefore, our answer is C.
