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2 answers:

galina1969 [7]3 years ago

8 0

31 yea I think so too

il63 [147K]3 years ago

7 0

31 I think I’m not sure may be wrong

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A city has a population of 310,000 people. Suppose that each year the population grows by 9%. What will the population be after

Leno4ka [110]

Answer: 644,800

Step-by-step explanation:

This can also be solved using the terms of Arithmetic Progressions.

Let the 13 years be number of terms of the sequences (n)

Therefore ;

T₁₃ = a + ( n - 1 )d , where a = 310,000 and d = 9% of 310,000

9% of 310,000 = 9/100 x 310,000

= 27,900

so the common difference (d)

d = 27,900

Now substitute for the values in the formula above and calculate

T₁₃ = 310,000 + ( 13 - 1 ) x 27,900

= 310,000 + 12 x 27,900

= 310,000 + 334,800

= 644,800.

The population after 13 years = 644,800.

3 0

3 years ago

30 Points!!

neonofarm [45]

Answer:

multiply the left side of the constant vector by the inverse matrix

Step-by-step explanation:

The matrix equation ...

AX = B

is solved by left-multiplying by the inverse of A:

A⁻¹AX = A⁻¹B

IX = A⁻¹B . . . . . the result of multiplying A⁻¹A is the identity matrix

X = A⁻¹B . . . . . B needs to be multiplied by the inverse matrix

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}-4&1\\3&2\end{array}\right]^{-1}\left[\begin{array}{c}9&7\end{array}\right]=\dfrac{1}{11}\left[\begin{array}{cc}-2&1\\3&4\end{array}\right]\left[\begin{array}{c}9&7\end{array}\right]=\left[\begin{array}{c}-1&5\end{array}\right]$