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garri49 [273]
3 years ago
9

Please help me this is a post test!

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

I cant see, Camera quaily is bad.

Step-by-step explanation:

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Somebody help me log (7x+2)-log 3=1​
Alex Ar [27]

Answer:

answer below :)

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x=−1−log(3)/7

Decimal Form:

x=−0.07469696…

give me brainly please

6 0
3 years ago
Chanelle deposits $7,500 into the bank. She does not withdraw or deposit money for 6 years. She earns 6% interest during that ti
koban [17]

Answer: a. $2700

b. $10200

Step-by-step explanation:

a. The interest she would have earned at the end of the 6 years can be gotten using the formula

= PRT/100

= $7500 × 6% × 6

= $7500 × 6/100 × 6

= $7500 × 0.06 × 6

= $2700

b. Her balance when she wants to withdraw the money would be:

= $7500 + $2700

= $10200

5 0
3 years ago
Nora is twice as old as Raj and half as old as Ethan. In 22 years' time. Ethan will be twice as old as Raj. Find Nora's current
Studentka2010 [4]

Answer:

44 because 22 multiplied by 2 is 44

5 0
2 years ago
A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,
Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

So

P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017

Probability of a defective item being produced on the first shift:

1% of 50%. So

P(A \cap B) = 0.01*0.5 = 0.005

What is the probability that it was manufactured during the first shift?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0
3 years ago
HELP QUICK LIKE RIGHT NOW!please
pogonyaev

Answer:

1/2 = 1/2

Step-by-step explanation:

5/10 is equal to 1/2 and 1/2 cant get smaller making you answer 1/2 = 1/2

8 0
3 years ago
Read 2 more answers
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