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3 years ago

Please help me with this one

Mathematics

1 answer:

Vladimir79 [104]3 years ago

8 0

Is 10 and 15 because they both have a value of .909

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An architect built a scale model of a sports stadium using a scale in which 2 inches represents 30 feet. The height of the sport

bija089 [108]

The height of the model in inches would be 6. if you multiply 30 until it reaches 180 you will have 6.

7 0

3 years ago

Twenty-eight slices of pizza cost $12. Approximately how much would 70 slices cost?

Mademuasel [1]

Answer:

$30.

Step-by-step explanation:

70/28 = 2.5

12 x 2.5 = 30

5 0

2 years ago

Complete the squar3

cricket20 [7]

9514 1404 393

Answer:

4
-2
4
2
-2±√2

Step-by-step explanation:

In order to fill the first blank, we need to look at the second line to see what the coefficient of x is.

1. x² + 4 x +2 = 0

The constant is subtracted from both sides to get the second line.

2. x² +4x =  -2 

The value that is added on the third line is the square of half the x-coefficient: (4/2)² = 4

3. x² +4x + 4  = -2 +4

On the fourth line, the left side is written as a square, and the right side is simplified. The square root is taken of both sides.

4. √(x +2)² = ±√ 2 

Finally, 2 is subtracted from both sides to find the values of x.

5. x =  -2 ±√2 

8 0

3 years ago

Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving

lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

$P(x=0) = ^nC_x P^x (1-P)^n^-^x$

$P(x=0) = ^5C_0 (0.4)^0 (1-0.4)^5^-^0$

$P(x=0) = ^5C_0 (0.4)^0 (0.60)^5$

$P(x=0) = 0.778$

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

$= 1 - P(X = 0)$

$= 1 - ^5C_0 (0.4)^0 * (0.6)^5$

$= 1 - 0.0778$

$= 0.9222$

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

$^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 (0.4)^2 (0.6)^3$

$= 0.6826$

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

$= 1 - [^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 * (0.4)^2 (0.6)^3]$

$= 1 - 0.6826$

$= 0.3174$

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0

3 years ago

Express the radical using the imaginary unit, i

Kipish [7]

Answer:

7i.

Step-by-step explanation:

Note : The given expression must be $\sqrt{-49}$ .

We have to write this radical value in the imaginary value.

The given value can be rewritten as

$\sqrt{-49}=\sqrt{49\times (-1)}$

$\sqrt{-49}=\sqrt{49}\times \sqrt{-1}$ $[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]$

$\sqrt{-49}=7\times i$ $[\because \sqrt{-1}=i]$

$\sqrt{-49}=7i$

Therefore, the required expression is 7i.

8 0

3 years ago