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adoni [48]
2 years ago
11

smiddle" class="latex-formula">
I need help with this problem​
Mathematics
2 answers:
horsena [70]2 years ago
7 0
The Correct answer: -2
Aloiza [94]2 years ago
4 0

~~-5=a-3\\\\\implies a =-5+3\\\\\implies a  = -2

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PLEASE HURRY ON A TEST!!<br><br> Given similar figures, find the length of the missing side.
liubo4ka [24]

Answer:

It would be A.10

Step-by-step explanation:

20/5 = 4

9/2.25= 4

40/10 = 4

6 0
3 years ago
Read 2 more answers
2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

5 0
3 years ago
10. What's the area of a slice of pizza from a large pizza with radius 9 inches cut into 6 slices?
Kipish [7]

Answer:

A

Step-by-step explanation:

A= r(pi)^2

A= 9 pi ^2

Hope it helps!

5 0
4 years ago
Value of the y-intercept of the graph of f(x) = e1–x – 1?
frozen [14]

Answer:

(0, e-1) or (0, 1.718) to the nearest thousandth.

Step-by-step explanation:

The y-intercept occurs when x = 0 so here we have:

y = e^(1 - 0) - 1

= e - 1

So the y-intercept is the point (0, e-1)

5 0
4 years ago
How can you find approximations of square roots?​
Likurg_2 [28]

Answer:

you can do a trial and improvement

Step-by-step explanation:

8 0
3 years ago
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