Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
he ratio of 3:1 involves 4 units. 3 men +1 woman.
Find how many people each unit represents:
4units 2476 people
Therefore each unit represents 2476/4 = 619 people per unit
Now, take the ratio, and multiply up:
3:1 => 3619:1619 => 1857:619 You check this is right by adding the two fractions:
1857 men + 619 women = 2476 people therefore, we are correct
The number of men more than women = Number of men - Number of women
= 1857-619 = 1238 and that is your answer
Answer:
low temperature= high temperature/2 or X= 74/2
Step-by-step explanation:
The low is 37 btw