You would set up the problem like this: 3n-25=38
To solve for n:
3n-25=38
+25 +25 (Add 25 to both sides)
3n=63
/3 /3 (Divide by 3 on both sides)
n=21
The answer is 21.
Answer:
a. N=25
b. X[bar]= 60.52
c. Y[bar]= 106.72
d. SSx= 115.24
e. ∑X*∑Y = 4036684
f. SSxy= 202020.3296
g. √(SSx*SSy)= 449.46
Step-by-step explanation:
Hello!
Using the attached data you need to calculate some statistics.
a) N
The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.
b.
The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52
∑X is listed in the second table.
c.
The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72
∑Y is listed in the second table.
d.
Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24
e.
∑X*∑Y =1513*2668= 4036684
f.
SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296
g.
√(SSx*SSy)= √(115.24*1753)= 449.46
I hope you have a SUPER day!
I assume the answer is 1/4
don't know if this might help but here
Step-by-step explanation:
(−∞,∞),{y|y∈R}
Answer:
Step-by-step explanation:
To calculate the speed of each one we proceed as follows:
speed=distance/time
a] Noah's speed:
distance=2.5 miles
time=3/5 hours
speed=(2 1/2)/(3/5)
=(5/2)/(3/5)
=5/2×5/3
=25/6
=4 1/6 mi/hr
Emily's speed
distance=3 3/4 miles
time=5/6 hour
thus
speed=(3 3/4)/(5/6)
=15/4)/(5/6)
=15/4×6/5
=4 1/2 mi/hr
Anna's speed:
distance=3 1/3 miles
time=3/5
speed=(3 1/3)/(3/5
=(10/3)/(3/5)
=10/3×5/3
=5 5/9 mi/hr
Anna was the fastest