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3 years ago

12

Kinetic and potential energies of a roller coaster I'm doing a portfolio

1 answer:

Brut [27]3 years ago

4 0

On a roller coaster<span>, </span>energy<span> changes from </span>potential<span>to </span>kinetic energy<span> and back again many times over the course of a ride. </span>Kinetic energy<span> is </span>energy<span> that an object has as a result of its motion. All moving objects possess </span>kinetic energy, which is determined by the mass and speed of the object.

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Explanation:

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Assuming that the tungsten filament of a lightbulb is a blackbody, determine its peak wavelength if its temperature is 3 200 K.

rosijanka [135]

Answer:

the peak wavelength when the temperature is 3200 K = $9.05625*10^{-7} \ m$

Explanation:

Given that:

the temperature = 3200 K

By applying Wien's displacement law ,we have

$\lambda _m$ T = 0.2898×10⁻² m.K

The peak wavelength of the emitted radiation at this temperature is given by

$\lambda _m$ = $\frac{0.2898*10^{-2} m.K}{3200 K}$

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Hence, the peak wavelength when the temperature is 3200 K = $9.05625*10^{-7} \ m$

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3 years ago

What is 9.7e-6 as a decimal

skelet666 [1.2K]

Answer:

See below

Explanation:

9.7e-6 is 9.7 x 10^-6 move the decimal 6 to the LEFT to get

= .0000097

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