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jenyasd209 [6]
3 years ago
14

An object initially traveling at a velocity of 52 m/s experiences an acceleration of 9.8 m/s^2 how much time will it take to com

e to rest
Physics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

5.3 seconds

Explanation:

Vx = Vx0 + Ax .T

A= de-acceleration

Vx =0   final at rest velocity

Vx0 = initial velocity

T= time to bring the object to a stop

therefore

0 = 52 m/s - (9.8 m/s^2) . T

-52 m/s/ -9.8 m/sec^2 =T

5.3 seconds= T

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<h3>1)</h3>

No,kinetic energy cannot be negative since its given by KE=mv²,mass cannot be negative and the square of speed cannot b negative.

<h3>2)</h3>

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<h3>3)</h3>

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The work done is zero

<h3>6)</h3>

w = f.d.cos \theta = f.d.cos0 = f.d

The work is just the product of the magnitude of the force exerted and the displacement of the object.

<h3>7)</h3>

0 <  \theta < 90 \\ 1 < cos \theta < 0

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<h3>8)</h3>

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<h3>Work is negative</h3>
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