1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Helga [31]
2 years ago
9

What speed should a satellite of mass 4,900 kg moving around

Physics
1 answer:
Rudiy272 years ago
8 0

Based on the calculations, the speed required for this satellite to stay in orbit is equal to 1.8 × 10³ m/s.

<u>Given the following data:</u>

  • Gravitational constant = 6.67 × 10⁻¹¹ m/kg²
  • Mass of Moon = 7.36 × 10²² kg
  • Distance, r = 4.2 × 10⁶ m.

<h3>How to determine the speed of this satellite?</h3>

In order to determine the speed of this satellite to stay in orbit, the centripetal force acting on it must be sufficient to change its direction.

This ultimately implies that, the centripetal force must be equal to the gravitational force as shown below:

Fc = Fg

mv²/r = GmM/r²

<u>Where:</u>

  • m is the mass of the satellite.
  • M is mass of the Moon.

Making v the subject of formula, we have;

v = √(GM/r)

Substituting the given parameters into the formula, we have;

v = √(6.67 × 10⁻¹¹ × 7.36 × 10²²/4.2 × 10⁶)

v = √(1,168,838.095)

v = 1,081.13 m/s.

Speed, v = 1.8 × 10³ m/s.

Read more on speed here: brainly.com/question/20162935

#SPJ1

You might be interested in
Find the initial velocity
Ivenika [448]

a = dv/t = (330-x)/1.5 =50

x= 330-75 = 255 m/s

Intial velocity 255 m/s

4 0
3 years ago
Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h
andreyandreev [35.5K]
Disagree.
Fluoresce objects will only glow when put under actual Ultraviolet light. This is due to the molecules becoming excited by the ultraviolet radiation.


Microwaves give micro-waves that are present in another spectrum of wave length and will not be able to fluoresce the molecules. If it’s not “ultra violet “.... it’s not going to glow.
4 0
3 years ago
Read 2 more answers
a raft of dimensions 2m wide by 3m long by .5m thick is floating in a pond if one fourth of the raf is submerged find the densit
11111nata11111 [884]

Answer:

250 kg/m3

Explanation:

The total volume of the raft is length times width times height

V = lwh = 2 * 3 * 0.5 = 3 m cubed

The volume of the raft that is submerged in water is 1/4 of total volume

3 /4 = 0.75 m cubed

Let water density = 1000 kg/m cubed and g = 10 m/s2

The buoyant force is equal to the weight of water displaced by the raft

F = 0.75 * 1000 * 10 = 7500 N

This force is balanced by the raft weight, so the weight of the raft is also 7500N

Mass of raft is 7500 / g = 7500 / 10 = 750 kg

Raft density is mass divided by volume = 750 / 3 = 250 kg/m3

8 0
3 years ago
a 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Find the total momentum of the system.
Hunter-Best [27]

Explanation:It is given that,

Mass of bumper car, m₁ = 202 kg

Initial speed of the bumper car, u₁ = 8.5 m/s

Mass of the other car, m₂ = 355 kg

Initial velocity of the other car is 0 as it at rest, u₂ = 0

Final velocity of the other car after collision, v₂ = 5.8 m/s

Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁

Using the conservation of linear momentum as :

p₁ = m₁v₁ = -342 kg-m/s

So, the momentum of the 202 kg car afterwards is 342 kg-m/s. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
A hula hoop is rolling along the ground with a translational speed of 26 ft/s. It rolls up a hill that is 16 ft high. Determine
nikklg [1K]

Answer:12.8 ft/s

Explanation:

Given

Speed of hoop v=26\ ft/s

height of top h=16\ ft

Initial energy at bottom is

E_b=\frac{1}{2}mv^2+\frac{1}{2}I\omega ^2

Where m=mass of hoop

I=moment of inertia of hoop

\omega=angular velocity

for pure rolling v=\omega R

I=mR^2

E_b=\frac{1}{2}mv^2+\frac{1}{2}mR^2\times (\frac{v}{R})^2

E_b=mv^2=m(26)^2=676m

Energy required to reach at top

E_T=mgh=m\times 32.2\times 16

E_T=512.2m

Thus 512.2 m is converted energy is spent to raise the potential energy of hoop and remaining is in the form of kinetic and rotational energy

\Delta E=676m-512.2m=163.8m

Therefore

163.8 m=mv^2

v=\sqrt{163.8}

v=12.798\approx 12.8\ ft/s

7 0
3 years ago
Other questions:
  • At what distance above the surface of the earth is the acceleration due to the earth's gravity 0.995 m/s2 if the acceleration du
    9·2 answers
  • Can anyone help me, I’m so stuck?
    6·1 answer
  • Help me slove this problem 115 divided by 2
    14·2 answers
  • A pair of parallel plates is charged by a 24-V battery. How much work is required to move a particle with a charge of-3.0uC from
    15·2 answers
  • You are driving down the road at 15 m/s you step on the gas and speed up with uniform acceleration of 2.5 m/s^2 for 0.80 seconds
    8·1 answer
  • 4- What force must be applied to a surface area of 0.0025m , to create a pressure ol<br>200.000Pa?​
    11·1 answer
  • Sometimes you wish you could go back in time and fix your mistakes but you can’t you can say sorry but it’s never enough what mo
    14·2 answers
  • An object traveling at a constant velocity of 15 m/s is experiencing no net
    9·1 answer
  • Which line represents a stationary object?<br> Position<br> Time
    15·1 answer
  • What part of an atom is involved in a chemical reaction?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!