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lidiya [134]
3 years ago
12

What is watt equivalent to in terms of kg,m and s

Physics
1 answer:
daser333 [38]3 years ago
3 0

F=ma=kg*m/s^2=N

Work=W=Force*d=N*m

P=W/time=N*m/s=kg*m^2/s^3=kg*m^2*s^-3=Watt

So 1 Watt of Power is equivalent to (kg*m^2)/s^3 or kg*m^2*s^-3


Any questions please feel free to ask. Thank you

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trapecia [35]

Answer:

abiotic

Explanation:

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3 years ago
En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8
Ivanshal [37]

Answer:

v1=18.46m/s

v2=29.8cm/s

Explanation:

We know that

A=10cm\\T=2s

the equation of the motion is

x=Acos(\omega t)\\

we can calculate w by using

\omega=\frac{2\pi}{T}=\frac{2\pi}{2}=\pi

Hence, we have that

x=10cm*cos(\pi t)\\

the speed will be

v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46\frac{cm}{s}\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8\frac{cm}{s}

hope this helps!

6 0
3 years ago
Cassie pulled the boat onto the ice and adjusted its sails. Once she got started she would be able to steer, change direction an
gladu [14]

Wind Energy is the kind of energy will Cassie uses to power the boat.

What is wind energy?

The method of producing electricity using air or wind currents that naturally occur in the earth's atmosphere is known as wind energy (or wind power). Electricity is produced by modern wind turbines that harness the kinetic energy of the wind. Wind passing across the turbine's blades is the initial step.

What is the major problem with wind energy?

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Learn more about wind energy: brainly.com/question/27997211

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8 0
2 years ago
All objects _<br> energy.
Alekssandra [29.7K]

Answer:

Explanation:

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8 0
3 years ago
A vessel with an unknown volume is filled with 10 kg of water at 90oC. Inspection of the vessel at equilibrium shows that 8 kg o
damaskus [11]

Hey there!

In this case, it is possible to solve this problem by using the widely-known steam tables which show that at 90 °C, the pressure that produces a vapor-liquid mixture at equilibrium is about 70.183 kPa (Cengel, Thermodynamics 5th edition).

Moreover, for the calculation of the volume, it is necessary to calculate the volume of the vapor-liquid mixture, given the quality (x) it has:

x=\frac{m_{steam}}{m_{total}}

Thus, since 8 kg correspond to liquid water, 2 kg must correspond to steam, so that the quality turns out:

x=\frac{2kg}{10kg} =0.20

Now, at this temperature and pressure, the volume of a saturated vapor is  2.3593 m³/kg whereas that of the saturated liquid is 0.001036 m³/kg and therefore, the volume of the mixture is:

v=0.001036m^3/kg+0.2(2.3593-0.001036 )m^3/kg=0.4727m^3/kg

This means that the volume of the container will be:

V=10kg*0.4727m^3/kg\\\\V=4.73m^3

Regards!

8 0
2 years ago
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