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3 years ago

Find the expression when a=-3 and b=-1: A^2-b^2=

Mathematics

1 answer:

muminat3 years ago

6 0

Well imma say -3^2–1^2=-8

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12) Find the value of x.

bixtya [17]

I’m sorry if I’m wrong but the equation be 3x+6=2x and if you solve that, x=6.

Explanation: 3x+6=2x
-3x. -3x
6=x

7 0

3 years ago

How do you calculate the LCM for 128 and 256

Neporo4naja [7]

Answer:

I think its 256

Step-by-step explanation:

The LCM of 128 and 256 is 256. Steps to find LCM. Find the prime factorization of 128 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2; Find the prime factorization of 256.

6 0

2 years ago

Read 2 more answers

Use the discriminant to find the number and type of solution for x^2+6x=-9

likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

$\displaystyle \large{D = {b}^{2} - 4ac}$

First, arrange the expression or equation in ax^2+bx+c = 0.

$\displaystyle \large{ {x}^{2} + 6x = - 9}$

Add both sides by 9.

$\displaystyle \large{ {x}^{2} + 6x + 9 = - 9 + 9} \\ \displaystyle \large{ {x}^{2} + 6x + 9 = 0}$

Compare the coefficients so we can substitute in the formula.

$\displaystyle \large{a {x}^{2} + bx + c = {x}^{2} + 6x + 9 }$

a = 1
b = 6
c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

$\displaystyle \large{D = {6}^{2} - 4(1)(9)} \\ \displaystyle \large{D = 36 - 36} \\ \displaystyle \large{D = 0}$

Since D = 0, the type of solution is one real root.

6 0

3 years ago

We have two urns. The first urn contains two balls labeled 1 and 2. The second urn contains three balls labeled 3, 4, and 5. We

Furkat [3]

Answer:

1 over 7

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help me i’ll give extra points

-BARSIC- [3]

Answer:

B and C

Step-by-step explanation:

Make rocket go down = less engine power and more weight

Pls mark brainiest :)

6 0

3 years ago