-2x + 6 = 30 - 6x
--> -2x + 6x = 30 - 6
<span>--> 4x = 24
</span><span>--> x = 24/4
</span><span>--> x = 6</span>
Answer:
I think its $1 every 4 oz
Step-by-step explanation:
Basing this off that 4 * 4 is 16
Okay, first we need to figure out what one would make. We need to figure out the area of the base x height. The diameter is 8 so we will cut that to 4 so we can do piR2! 3.14x16 would be 50.24. Then we mutiply that by 10 to get 502.4cm3! Okay, now we would divide 2000/502.4 to find out how many times we would have to make the containers to get to 2000. The answer is 3.98, which we will have to round up since its asks for the minimum and you cant make a container 3.98 times. So the answer is 4!
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)
Answer:
52°
Step-by-step explanation:
<em>here's</em><em> </em><em>your</em><em> solution</em>
<em>=</em><em>></em><em> </em><em>we </em><em>know</em><em> </em><em>that</em><em> </em><em>the </em><em>measure</em><em> </em><em>of</em><em> </em><em>angle</em><em> of</em><em> </em><em>rectangle</em><em> </em><em>is </em><em> </em><em>9</em><em>0</em><em>°</em>
<em>=</em><em>></em><em> </em><em> </em><em>3</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>X </em><em> </em><em>=</em><em> </em><em>9</em><em>0</em><em>°</em>
<em>=</em><em>></em><em> </em><em>X </em><em>=</em><em> </em><em>9</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>3</em><em>8</em><em>°</em>
<em>=</em><em>></em><em> </em><em>X </em><em>=</em><em> </em><em>5</em><em>2</em><em>°</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>