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neonofarm [45]
3 years ago
13

A person carries a mass of 10 kg and walks along the +x-axis for a distance of 100m with a constant velocity of 2 m/s. What is t

he work done by this person?
A) 20 J

B) None of the other choices is correct.

C) 0 J

D) 200 J
Physics
2 answers:
mezya [45]3 years ago
5 0

Answer:

Work done, W = 0

Explanation:

It is given that,

Mass of the object, m = 10 kg

Distance covered by the person, d = 100 m

Speed of the person, v = 2 m/s

We need to find the work done by this person. We know that the product of force and distance is equal to the work done by the person. Mathematically,

W=F\times d

W=m\times a\times d    

Since, the acceleration is equal to the rate of change of velocity. Here, the person is moving the mass with a constant velocity. So, there is no change in velocity, a = 0

As a result, the work done by the person is 0 J. So, the correct option is (c). Hence, this is the required solution.      

gizmo_the_mogwai [7]3 years ago
3 0
Since the direction of the force and the direction of the path is perpendicular, the person is not doing any physical work.
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a car advertisement states that a certain car can accelerate from rest to 70km/h in 7 seconds. find the cars acceleration
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3 years ago
A Viking ship roller coaster at the fair has a mass of 36,000 kg. If at its peak it reaches a height of 20 m off the ground, how
adell [148]

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Explanation:

Given that,

Mass of a ship roller coaster is 36,000 kg.

It reaches a height of 20 m off the ground

We need to find the gravitational potential energy does it have. The formula for the gravitational potential energy ios given by :

E = mgh

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E = 36,000 kg × 9.8 m/s² × 20 m

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8 0
3 years ago
A ball rolls up a ramp with a velocity of 8.0 m/s. How high up the ramp does it travel?
Flura [38]

The greatest height the ball will attain is 3.27 m

<h3>Data obtained from the question</h3>
  • Initial velocity (u) = 8 m/s
  • Final velocity (v) = 0 m/s (at maximum height)
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Maximum height (h) =?

The maximum height to which the ball can attain can be obtained as follow:

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Collect like terms

0 – 64 = –19.6h

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Divide both side by –19.6

h = –64 / –19.6h

h = 3.27 m

Thus, the greatest height the ball can attain is 3.27 m

Learn more about motion under gravity:

brainly.com/question/13914606

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2 years ago
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