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dlinn [17]
3 years ago
12

______ Is the distance and direction of an object's change in position from its starting point.

Physics
2 answers:
Vsevolod [243]3 years ago
5 0

Answer:

Distance Is the distance and direction of an object's change in position from its starting point.

Mumz [18]3 years ago
5 0
Displacement because of you displace something it is not going to be in its original place for instants if you put a vase on a shelf and you move it it’s is not going to be on the shelf anymore
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Two particles, each of charge Q, are fixed at opposite corners of a square that lies in the plane of the page. A positive test c
amid [387]

Answer:

The magnitude of the net force is √2F.

Explanation:

Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:

F_N=\sqrt{F^{2}+F^{2}}\\\\F_N=\sqrt{2F^{2}}\\\\F_N=\sqrt{2}F

Then, it means that the net force acting on the test charge has a magnitude of √2F.

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3 years ago
Please see the picture​
Tpy6a [65]

Answer:

t.f. are you sure that's english? it looks like not a real thing

Explanation:

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3 years ago
Are the two atoms shown below in the image from the same element?
kvasek [131]

The answer is yes

They are isotopes.

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3 years ago
A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 1
Bumek [7]

Answer:

202.8m

Explanation:

Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.

First calculate the total time travelled by using the second equation of motion

h = Ut + 1/2gt^2

Let assume that u = 0

And h = 3.5

Substitute all the parameters into the formula

3.5 = 1/2 × 9.8 × t^2

3.5 = 4.9t^2

t^2 = 3.5/4.9

t^2 = 0.7

t = 0.845s

To know how far the cannonball travel, let's use the equation

S = UT + 1/2at^2

But acceleration a = 0

T = 2t

T = 1.69s

S = 120 × 1.69

S = 202.834 m

Therefore, the distance travelled by the cannon ball is approximately 202.8m.

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2 years ago
Diffrence between FMRI and MRI?
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2 years ago
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