Answer:
Magnitude of force, F = 11 Newtons
Explanation:
Charge 1, 
Charge 2, 
The separation between the charges is, r = 0.22 m
We have to find the magnitude of the force between two point charges. It can be calculated using the formula as :
F = 11.03 N
or
F = 11 Newtons
Hence, this is the required solution.
In order to get a sample of air that is 23 km above the ground, the rocket must rise by that height.
Draw a diagram (shown below) t represent the problem.
The distance h₁ is traveled from A to B with an upward acceleration of 17 m/s² over 30 s. The distance traveled is
h₁ = (1/2)(17 m/s²)(30 s)² = 7650 m = 7.65 km
At point B, the velocity attained is
V = (17 m/s²)30s) = 510 m/s
The distance h₂ is traveled from B to C with gravitational deceleration of -9.8 m/s². The distance traveled is given by
(510 m/s)² - 2(9.8 m/s²)h₂ = 0
h₂ = 13270.4 m = 13.27 km
The total height attained by the rocket is
h₁ + h₂ = 7.65 + 13.27 = 20.92 km
This height falls short of the desired height of 23 km.
Answer:
The rocket does not travel high enough to sample the air at a height of 23 km.
Answer:
a) 4 s
b) 36 m/s²
c) 54 m
Explanation:
s = 2t³ – 24t + 6
a) Find t when v = 72 m/s.
v = ds/dt
v = 6t² – 24
72 = 6t² – 24
6t² = 96
t = 4
b) Find a when v = 30 m/s.
a = dv/dt
a = 12t
When v = 30:
30 = 6t² – 24
6t² = 54
t = 3
a = 36
c) Find Δs between t = 1 and t = 4
Δs = (2(4)³ – 24(4) + 6) – (2(1)³ – 24(1) + 6)
Δs = 38 – (-16)
Δs = 54
The elastic potential energy increases by a factor of 9
Explanation:
The elastic potential energy of a bowstring is given by
(1)
where
k is the spring constant
x is the elongation of the bowstring
Hooke's law states the relationship between the force applied and the elongation of an elastic object:
where
F is the force applied
x is the elongation
We can rewrite it as
And substituting into (1),
In this problem, the force applied to the bowstring is tripled,
F' = 3F
So the final elastic potential energy is:
So, the elastic potential energy increases by a factor of 9.
Learn more about potential energy:
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brainly.com/question/10770261
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Answer:
ocean covers 71 percent of the earth
