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Mamont248 [21]
2 years ago
10

What are some examples of static force?

Physics
2 answers:
Stella [2.4K]2 years ago
4 0
Glass on glass,tire on concrete,tire on snow

tigry1 [53]2 years ago
3 0
Some examples of static friction between two substances or objects are: glass on glass, tire on concrete, tire on snow, tire on a wet surface and steel on steel. Friction is the force between two objects in contact with each other that will resist an attempt to move them.
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What is the electric potential of a 2.2 µC charge at a distance of 6.3 m from the charge? Recall that Coulomb’s constant is k =
Doss [256]
The first part of the question is 3,100 V.

The second part of the question is 200 V.
6 0
3 years ago
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What is the magnitude of the velocity of a 25 kg mass that is moving with a momentum of 100 kg*m/s?
Gekata [30.6K]

Answer:

v= 4 m/s

Explanation:

Momenutm is, by definition, the product of mass and velocity.

p = mv

Let's replace what we know and solve for whatever's left

100 kg\cdot m/s = 25kg \cdot v \rightarrow v= 4 m/s

7 0
2 years ago
What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b? A. –7 ab B. `-7 a/b ` C
algol13

Answer:

C. -12 ab

Explanation:

The restoring force on a spring is given by Hooke's law:

F=-kx

where

k is the spring constant

x is the stretched (or compressed) displacement of the spring

In this problem we have:

k = 4a

x = 3b

Substituting into the equation, we find:

F=-(4a)(3b) = -12 ab

And the negative sign means that the direction of the force (negative) is opposite to the direction of the displacement (positive).

3 0
3 years ago
Currents during lightning strikes can be up to 50000 A (or more!). We can model such a strike as a 47500 A vertical current perp
Rufina [12.5K]

Answer:

57 N

Explanation:

Force on a current carrying conductor in a magnetic field

B = 12 X 10⁻⁴ T

= Bil where B is magnetic field , i is current and l is length of conductor

force required = 12 x10⁻⁴ x 47500 x 1

= 57 N

6 0
2 years ago
A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
lana66690 [7]

Answer:

420000N

Explanation:

Given parameters:

Mass of the train  = 5.6 x 10⁵kg

Acceleration  = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

   Force  = mass x acceleration

Resultant force that acts on the train is given below;

 Force  = 5.6 x 10⁵kg  x 0.75m/s²  = 420000N

7 0
2 years ago
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