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kenny6666 [7]
3 years ago
8

If

class="latex-formula"> and g(x)=3x, what is (f\circ g)(2)?
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

\large\boxed{34}

Step-by-step explanation:

f(x) = x^2 - 2

g(x) = 3x

(fog)(2)

Find g(2)

g(x) = g(2)

x=2

3x = 3(2) = 6

g(2) = 6

Find f(6)

f(x) = x^2-2

Substitute

f(6) = x^2 - 2

x^2 - 2 = 6^2 - 2

36 - 2 = 34

\large\boxed{34}

Hope this helps :)

jek_recluse [69]3 years ago
4 0

Answer:

\boxed{f(6) = 34}

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as (f \circ g)(2), we are replacing the x values in the g(x) function with 2 and simplifying the expression.

g(2) = 3(2)

g(2) = 6

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

f(6) = (6)^2-2

f(6) = 36-2

f(6) = 34

Therefore, when we compose the functions, our final answer is \bold{f(6) = 34}.

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