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astraxan [27]
2 years ago
8

-12=-5-6n+11 solve it for me

Mathematics
2 answers:
Lana71 [14]2 years ago
8 0
I think 3=n

I hope that helps!!!!!!

: )
borishaifa [10]2 years ago
6 0
-5-6n+11=-12
-5-6n=-1
-6n=6
/-1    /-1

n=-1
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1) A rectangle has the lengths shown <br> Find the perimeter of the rectangle.
maks197457 [2]

Hi there! :)

\large\boxed{P = 32cm}

Find the perimeter by solving for y.

We know that a rectangle contains two pairs of parallel and congruent sides, therefore:

5y - 1 = 2y + 8

We can solve for y using this expression. Begin by subtracting 2y from both sides:

5y - 2y - 1 = 2y - 2y + 8

3y - 1 = 8

Add 1 to both sides:

3y - 1 + 1 = 8 + 1

3y = 9

Divide both sides by 3:

y = 3

Recall that the perimeter of a rectangle is:

P = 2l + 2w

Plug in the given expressions for the side lengths to find one equation:

P = 2(5y - 1) + 2(y - 1)

Simplify by distribution:

P = 10y - 2 + 2y - 2

Combine like terms:

P = 12y - 4

Plug in the solved value of y into this equation:

P = 12(3) - 4

P = 36 - 4

P = 32 cm.

3 0
2 years ago
Evaluate the numerical expression. 9.6 – 10.8 ÷ 0.6
Lorico [155]
Hello :)

The answer is -8.4

Hope this helps and have a great day!
3 0
3 years ago
Read 2 more answers
What expression is equivalent to 10-8
Ivahew [28]
There are many expressions equivalent, it just needs the answer to also equal 2.

2×1
3-1
4÷2
1+1

so on
7 0
2 years ago
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PLEASE ANSWER ASAP!!!!
Arlecino [84]

We'll use the notation \textrm{Arcsin } x for the principal value and \arcsin x for all the values:


\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k


Part I


\sin(\theta/2) = \frac 1 2


\theta/2 = \arcsin \frac 1 2


Part II. In our range we can write


\sin(\theta/2) = \sin(\frac \pi 6)


\theta/2 = \frac \pi 6 \textrm{   or   } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}


Part III.


\theta = \frac \pi 3 \textrm{   or   } \theta = \frac{5\pi}{3}


Part IV.


\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k

\theta = \frac \pi 3 + 4 \pi k \textrm{   or   } \theta = \frac{5 \pi}{3} + 4\pi k  \quad \textrm{integer } k



5 0
2 years ago
Factor out the GCF of 64−32x
Mekhanik [1.2K]

Answer: 32

Step-by-step explanation:

4 0
3 years ago
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