1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rudiy27
4 years ago
12

BEST ANSWER GETS BRANLIEST

Mathematics
1 answer:
s344n2d4d5 [400]4 years ago
4 0
The answer is 9.1x10^9Hope this helps! Don't forget to give me a
<span>BRANLIEST</span>
You might be interested in
Question in the picture
wlad13 [49]

Answer:

uh uh uh

Step-by-step explanation:

5 0
3 years ago
What is the Y 2(7y−1)=40
MissTica

Answer:

3

Step-by-step explanation:

2(7y−1)=40

14y-2=40

14y=40+2

14y=42

y=3

please mark as brainliest

5 0
3 years ago
Read 2 more answers
Find the volume of this triangular prism.​
True [87]

Answer:

7 * 4 * 12 = 336sq cm

Step-by-step explanation:

Hoped this helped

4 0
3 years ago
A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

P (E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

{20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

{3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

                                                            =\frac{3}{190}\\

                                                            =0.01579\\\approx0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0
3 years ago
Rewrite sqr-100 +26 in complex number notation
Morgarella [4.7K]

Answer:

26 + 10i is your answer.

8 0
3 years ago
Other questions:
  • Expand the square (x + 4)2
    7·1 answer
  • The sum of two numbers is 20. One number is three times as large as the second
    13·1 answer
  • The percent, X , of shrinkage o n drying for a certain type of plastic clay has an average shrinkage percentage :, where paramet
    7·1 answer
  • Can someone help meeee ASAP. For 10 points
    13·1 answer
  • Dan is watching The Birds in his backyard. Of the birds he watches, 9. Of them,or 45%, are sparrows. How many birds are in his b
    9·1 answer
  • Which number is the largest?
    13·2 answers
  • In how many ways can a photographer at a wedding arrange six people in a row, including the bride and groom, if a) the bride mus
    5·1 answer
  • -3x(x + y) +5y<br> if x=2 <br> y= -5
    6·2 answers
  • Need help graphing ASAP
    7·1 answer
  • Is this right (plzzz help
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!