Answer:
Graph C
Step-by-step explanation:
Hi there!
The given linear equations are organized in slope-intercept form: 
where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept, or the value of y when the line crosses the y-axis.
y = 2x + 4
Here, the <em>b</em> value is 4. Therefore, the y-intercept of this line is 4.
y = -3x - 2
Here, the <em>b</em> value is -2. Therefore, the y-intercept of this line is -2.
To identify the graph that models these equations, we just have to look for the graph where the lines cross the y-axis at 4 and -2.
The only graph that does this is graph C.
I hope this helps!
Answer: The formula is (b1 + b2)h+PH
Step-by-step explanation:
At the start, the tank contains
(0.02 g/L) * (1000 L) = 20 g
of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.
Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of
(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s
In case it's unclear why this is the case:
The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.
So the amount of chlorine in the tank changes according to
which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):
![\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5B%5Cdfrac%7Bc%28t%29%7D%7B%28200-3t%29%5E%7B5%2F3%7D%7D%5Cright%5D%3D0)
There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :
![\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7Bc%28t%29%3D%5Cdfrac1%7B200%7D%5Csqrt%5B3%5D%7B%5Cdfrac%7B%28200-3t%29%5E5%7D5%7D%7D)
325*89.1
Let's decompose this into:
325 = 300 + 25
89.1 = 80 + 9 + 0.1
Then we have the multiplication:
(300 + 25)*(80 + 9 + 0.1)
Let's distribute the multiplication:
300*80 + 300*9 + 300*0.1 + 25*80 + 25*9 + 25*0.1
So now we have 6 multiplications that are a lot easier to solve than the initial one that we had.
Then the list of six multiplications involved in solving this problem are:
300*80 = 24,400
300*9 = 2,700
300*0.1 = 30
25*80 = 2,000
25*9 = 225
25*0.1 = 2.5
Now we add all of those and get:
325*89.1 = 24,400 + 2,700 + 30 + 2,000 + 225 + 2.5 = 28,957.5
Answer:
x=8 x=-2
Step-by-step explanation:
|x-3| -10=-5
Add 10 to each side
|x-3| -10+10=-5+10
|x-3| =5
Now separate into two equations , one positive and one negative
x-3 = 5 x-3 = -5
Add 3 to each side
x-3+3 = 5+3 x-3+3 = -5 +3
x=8 x=-2
