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Anit [1.1K]
2 years ago
11

Can someone help me with this

Mathematics
2 answers:
xxMikexx [17]2 years ago
6 0

Answer:

The first one is 45 hours

The second is 1361

koban [17]2 years ago
4 0
Answers
25.45
26.1361
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y=-4-2x+2

add -4 and +2.

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y=-2x-2

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What is the value of x in 2(5x) = 14?
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Step-by-step explanation:

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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 72 type K batteries and a sample of 49
rewona [7]

Answer:

Given:

For battery k(sample 1):

Sample size, n = 75

Sample mean, X' = 9.41

Standard deviation = 0.723

Mean u1 =???

For battery Q(sample 2):

Sample size, n = 49

Sample mean, X' = 9.69

Standard deviation = 0.257

Mean u2 =???

Significance level = 0.05

1) The null and alternative hypotheses, will be given as:

H0 : u1 - u2 = 0

H1 : u1 - u2 ≠ 0

2) This is a two tailed test.

For the test statistic, we have :

Z_o = \frac{X'_1 - X'_2}{\sqrt{\frac{(\sigma_1)^2}{n_1} + \frac{(\sigma_2)^2}{n_2}}}

= \frac{9.41 - 9.69}{\sqrt{\frac{(0.723)^2}{75} + \frac{(0.257)^2}{49}}} = - 3.018

≈ 3.02

The Zo = - 3.02

3) For the p value, using excel, we have:

2 * P(Z > (-3.018))

= 2 * NORMDIST (-3.018, 0, 1, true)

= 0.00254

For critical value:

Zcritical = Za/2 = 0.05/2

Zcritical = 0.025

We have alternative hypothesis,

H1 : u1 - u2 ≠ 0.

Therefore we reject null hypothesis H0 if Zo > Zcritical

4) We reject null hypothesis H0 if Zo > Zcritical. At 0.05 level of significance, there is not enough evidence to conclude that mean u1 and mean u2 are different.

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